All categories

3 years ago

How does the moon affect the Earth's tides?

Chemistry

2 answers:

stich3 [128]3 years ago

3 0

Answer:

I'm pretty sure the moon's gravity pulls on the tides.

alukav5142 [94]3 years ago

3 0

It is b, the moons gravity pulls the tides

explanation:
- The Moon's gravitational pull generates something called the tidal force. The tidal force causes Earth—and its water—to bulge out on the side closest to the Moon and the side farthest from the Moon. These bulges of water are high tides.

You might be interested in

What is the concentration of a 0.750 l solution that contains 52.0 g of glucose (c6h12o6)?

vodka [1.7K]

Concentration of Solutions is oftenly expressed in Molarity. Molarity is the number of moles of solute dissolved per volume of solution.

Molarity = Moles / Volume
As,
Moles = Mass / M.mass
So,
Molarity = Mass / M.mass × Volume ---- (1)

Data Given;
Volume = 0.750 L

Mass = 52 g

M.mass = 180 g/mol

Putting Values in eq.1,

Molarity = 52 g ÷ (180 g.mol⁻¹ × 0.750 L)

Molarity = 0.385 mol.L⁻¹

7 0

3 years ago

The current scientific verdict on the phlogiston theory demonstrates which two of the following principles?

masha68 [24]

Answer:

The two valid principles are:

Scientific theories can be replaced by better theories.

An experiment can disprove a theory that scientists have accepted.

Explanation:

The scientific knwoledge is not inmutable; it may (and does) change with new discoveries.

In fact, scientific theories cannot be proved right, instead they are constantly tested to try to disprove them. This is what the principle that theories are falsiable means.

As long as a scientific theory is not disproved it remains valid, but new discoveries may lead, eventually, to its disprovement.

Scientific knowledge evolves because new procedures, new technologies, and new evidence leads to a better understanding and better explanations.

5 0

3 years ago

The density of concentrated ammonia, which is 28.0% w/w nh3, is 0.899 g/ml. what volume of this reagent should be diluted to 1.0

vlada-n [284]

Answer: 2.4 ml

Solution :

Molar mass of $NH_3$ = 17 g/mole

Given,: 28% w/w of $NH_3$ solution means 28 g of ammonia in 100 g of solution.

Mass of solution = 100 g

Now we have to calculate the volume of solution.

$Volume=\frac{Mass}{Density}=\frac{100g}{0.899g/ml}=111.2ml$

Molarity : It is defined as the number of moles of solute present in one liter of solution.

$Molarity=\frac{n\times 1000}{V_s}$

where,

n = moles of solute $NH_3=\frac{\text {given mass}}{\text {molar mass}}=\frac{28}{17}=1.65moles$

$V_s$ = volume of solution in liter = 0.11 L

Now put all the given values in the formula of molarity, we get

$Molarity=\frac{1.65moles}{0.11L}=15mole/L$

Using molarity equation:

$M_1V_1=M_2V_2$

$15\times V_1=0.036\times 1.0\times 10^{3}$

$V_1=2.4ml$

6 0

3 years ago

Which substance is the oxidizing agent in the following reaction? Fe2S3 + 12HNO3 → 2Fe(NO3)3 + 3S + 6NO2 + 6H2O Which substance

aleksandr82 [10.1K]

Answer:

HNO3 is the oxidizing agent

Explanation:

Step 1:

The oxidizing agent is responsible to oxidize another. but itself undergoes a reduction .

Fe2S3:

Fe has an oxidation number of +3

S has an oxidation number of -2

HNO3:

O has an oxidation number of -2 ( we have 3 times O so this makes -6)

H has an oxidation number of +1

N has an oxidation number of +5

Fe(NO3)3

O has an oxidation number of -2 ( we have 3 times O so this makes -6)

Fe has an oxidation number of +3

Since NO3 has an oxidation number of -1; N has an oxidation number of +5

S alone has an oxidation number of 0

NO2:

O has an oxidation number of -2 (we have 2 times O, this makes -4)

N has an oxidation number of +4

Fe doesn't change from oxidation number. It stays +3

N goes from +5 to +4 → this is a reduction

S goes from -2 to 0 → this is an oxidation

The reducing agent is the compound that contributes the oxidized species (S).

The oxidizing agent contributes the reducing species (N)

The answer is HNO3

5 0

3 years ago

Which notation represents an atom of sodium with an atomic number of 11 and a mass number of 24

sukhopar [10]

Na24 is the notation

6 0

3 years ago

Read 2 more answers