All categories

3 years ago

How does the moon affect the Earth's tides?

Chemistry

2 answers:

stich3 [128]3 years ago

3 0

Answer:

I'm pretty sure the moon's gravity pulls on the tides.

alukav5142 [94]3 years ago

3 0

It is b, the moons gravity pulls the tides

explanation:
- The Moon's gravitational pull generates something called the tidal force. The tidal force causes Earth—and its water—to bulge out on the side closest to the Moon and the side farthest from the Moon. These bulges of water are high tides.

You might be interested in

A solution contains 0.182 molmol NaClNaCl and 0.897 molH2OmolH2O. Calculate the vapor pressure of the solution at 55 ∘C∘C. The v

solong [7]

Answer:

Vapor pressure of solution is 78.2 Torr

Explanation:

This is solved by vapor pressure lowering:

ΔP = P° . Xm . i

Vapor pressure of pure solvent (P°) - vapor pressure of solution = P° . Xm . i

NaCl → Na⁺ + Cl⁻ i = 2

Let's determine the Xm (mole fraction) These are the moles of solute / total moles.

Total moles = moles of solvent + moles of solute

Total moles = 0.897 mol + 0.182 mol → 1.079 mol

0.182 / 1.079 = 0.168

Now we replace on the main formula:

118.1° Torr - P' = 118.1° Torr . 0.168 . 2

P' = - (118.1° Torr . 0.168 . 2 - 118.1 Torr)

P' = 78.2 Torr

5 0

3 years ago

PLEASE ANSWER ASAP AND SHOW WORK: A camping stove uses a 5.0 L propane tank that holds 68.0 moles of liquid C3H8. How large a co

seropon [69]

Answer: The volume of the container needed is 554.6 L

Explanation:

To calculate the volume of the gas, we use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of the gas = 3.0 atm

V = Volume of the gas = ? L

T = Temperature of the gas = $25^oC=[25+273]K=298K$

R = Gas constant = $0.0821\text{ L.atm }mol^{-1}K^{-1}$

n = number of moles of propane gas = 68.0 moles

Putting values in above equation, we get:

$3.0atm\times ?L=68mol\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 298K\\\\V=\frac{68\times 0.0821\times 298}{3.0}=554.6L$

Hence, the volume of the container needed is 554.6 L

6 0

3 years ago

Given: Fe2O3(s) + 3 CO(g) –––––> 2 Fe(s) + 3 CO2(g); ΔH° = –26.8 kJ FeO(s) + CO(g) –––––> Fe(s) + CO2(g); ΔH° = –16.5 kJ d

Tpy6a [65]

Answer:

ΔH° = + 6.2 kJ

Explanation:

Fe₂O₃(s) + 3CO(g) –––––> 2 Fe(s) + 3 CO₂(g); ΔH° = –26.8 kJ ......... ( 1 )

FeO(s) + CO(g) –––––> Fe(s) + CO₂(g); ΔH° = –16.5 kJ .........( 2 )

Multiplying equation ( 2 ) by 2 and subtracting it from ( 1 )

Fe₂O₃(s) + 3CO(g) -2 FeO(s) - 2CO(g) ––> 2 Fe(s) + 3 CO₂(g) - 2Fe(s) - 2CO₂(g) ΔH° = –26.8 kJ - ( 2 x –16.5 kJ )

Fe₂O₃(s) + CO(g) -2 FeO(s)––> CO₂(g) ΔH° = –26.8 kJ + 33 kJ

Fe₂O₃(s) + CO(g) ––>2 FeO(s) +CO₂(g) ΔH° = + 6.2 kJ

Required ΔH° = + 6.2 kJ Ans .

8 0

3 years ago

How many moles of copper are there in 6.93 g of copper sample pls be quick

Alex_Xolod [135]

Molar mass of copper=63.5g/mol
Given mass=6.93g

$\\ \sf\longmapsto No\:of\;moles=\dfrac{Given\:mass}{Molar\:mass}$

$\\ \sf\longmapsto No\:of\:moles=\dfrac{6.93}{63.5}$

$\\ \sf\longmapsto No\:of\:moles=0.109\approx 1.11moles$

7 0

2 years ago

Read 2 more answers

Solving and balancing chemical equations

Rufina [12.5K]

Those are your answer i don’t know what 6 is though sorry. Have a good day

3 0

3 years ago