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3 years ago

Most fuel gases used for welding are

Chemistry

2 answers:

QveST [7]3 years ago

8 0

Acetylene which has a two stage reaction

NikAS [45]3 years ago

6 0

Acetylene is the only fuel gas suitable for gas welding because of its favourable flame characteristics of both high temperature and high propagation rates. Other fuel gases, such as propane, propylene or natural gas, produce insufficient heat input for welding but are used for cutting, torch brazing and soldering.

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Compound 2 contains 2.0g of hydrogen and 32.0g oxygen. What is the percent compound of each element?

Dmitriy789 [7]

Note down the formula below

$\boxed{\sf Mass\%\;of\; element=\dfrac{Mass\:of\:the\: element}{Mass\;of\:the\: compound}\times 100}$

Mass of the compound

$\\ \sf\longmapsto 32+2=34g$

Mass % of Hydrogen:-

$\\ \sf\longmapsto \dfrac{2}{34}\times 100$

$\\ \sf\longmapsto \dfrac{1}{17}\times 100$

$\\ \sf\longmapsto 5.8\%$

Mass % of Oxygen:-

$\\ \sf\longmapsto \dfrac{32}{34}\times 100$

$\\ \sf\longmapsto \dfrac{16}{17}\times 100$

$\\ \sf\longmapsto 94.2\%$

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Mice21 [21]

I’m not sure what the answer is but I hope someone can help!! Maybe answer choice B?

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C₃ H8<br> What is the subscript for carbon in this molecule?

Mars2501 [29]

Answer:

Explanation:

Subscript basically tells you the number of element or ions present in a compound. In this case the subscript of carbon which is 3 denotes that only three carbon atoms is present in the compound.

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3 years ago

*<br> What is the volume, in liters, of 12.0 kg of H2 at STP?

neonofarm [45]

Answer:

According to Avogadro's law, the volume of one mole of any gas at Standard Temperature and Pressure (STP = 273 K and 1 atm) is 22.4 L. Two important Gas Laws are required in order to convert the experimentally determined volume of hydrogen gas to that at STP. 1.

Explanation:

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In an Honors organic chemistry lab, a student devised an experiment in which she would treat benzoic acid with t-butanol in an a

oksian1 [2.3K]

Answer:

Check the explanation

Explanation:

Kindly check the attached images below to see the step by step explanation to the question above.

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