Answer:
a) ![A=5m/s^2](https://tex.z-dn.net/?f=A%3D5m%2Fs%5E2)
b) ![V=25m/s](https://tex.z-dn.net/?f=V%3D25m%2Fs)
Explanation:
From the question we are told that:
Velocity ![v=90km/h=25m/s](https://tex.z-dn.net/?f=v%3D90km%2Fh%3D25m%2Fs)
Time ![t=5.0s](https://tex.z-dn.net/?f=t%3D5.0s)
a)
Generally From Newton's motion equation for Average acceleration is mathematically given by
![A=\frac{V-U}{t}](https://tex.z-dn.net/?f=A%3D%5Cfrac%7BV-U%7D%7Bt%7D)
Since its from Rest Therefore
![U=0](https://tex.z-dn.net/?f=U%3D0)
![A=\frac{25m/s-0}{5s}](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B25m%2Fs-0%7D%7B5s%7D)
![A=5m/s^2](https://tex.z-dn.net/?f=A%3D5m%2Fs%5E2)
b)
Generally the equation for Average Velocity is mathematically given by
![V=u+at](https://tex.z-dn.net/?f=V%3Du%2Bat)
![AT t=1.0s\\\\V=0+5(1)](https://tex.z-dn.net/?f=AT%20t%3D1.0s%5C%5C%5C%5CV%3D0%2B5%281%29)
![V=5m/s](https://tex.z-dn.net/?f=V%3D5m%2Fs)
![AT t=2.0s\\\\V=0+5(2)](https://tex.z-dn.net/?f=AT%20t%3D2.0s%5C%5C%5C%5CV%3D0%2B5%282%29)
![V=10m/s](https://tex.z-dn.net/?f=V%3D10m%2Fs)
![AT t=5.0s\\\\V=0+5(5)](https://tex.z-dn.net/?f=AT%20t%3D5.0s%5C%5C%5C%5CV%3D0%2B5%285%29)
![V=25m/s](https://tex.z-dn.net/?f=V%3D25m%2Fs)
The outer surface of the glass expands faster than the inside surface since glass is a fairly good thermal insulator. The outer surface tries to expand without the inner surface doing so at the same time. This is the secret of Pyrex glass. It is more conductive to heat and the inner and outer surface expand (and contract) at the same time.
The initial velocity (its speed before falling off) is approximately 1.95 m/s
A. Between asteroids C and D because gravitational attraction is greatest with increased mass.
Answer:
The two possible frequencies of the other player's note are 437.3 Hz and 442.7 Hz
Explanation:
Given Data
f₁=440 Hz
fₐ=2.7 beats per seconds
The beat frequency is equal to the difference in the frequencies of the two original waves:
So
f
=|(f₁±fₐ)|
First to Solve for (-) Sign we get
f=|(440-2.7)|
f=437.3 Hz
Now for Solve for (+) Sign we get
f=|(440+2.7)|
f=442.7 Hz
The two possible frequencies of the other player's note are 437.3 Hz and 442.7 Hz