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avanturin [10]
3 years ago
7

complete the analogy: 1. speed: velocity;______:______ a. acceleration:velocity b. distance:displacement c. speed:acceleration d

. time:scalar 2. positive acceleration:_____: zero acceleration:constant velocity a. constant speed b. decreasing velocity c. increasing velocity d. zero velocity
Physics
2 answers:
Paraphin [41]3 years ago
7 0

Velocity is the vector,
     made up of the scalar speed + direction of speed

b).  Displacement is the vector,
           made up of the scalar distance + direction of distance
maks197457 [2]3 years ago
6 0
B.
distance is used to calculate speed

displacement is used to calculate velocity

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Whitepunk [10]
When a body is moving in circular path at a distance r from its center its velocity at any instant will be directed tangentially. This is what we call tangential velocity. It is calculated as follows:

Vt = r(ω)

where ω = 5 rev/s (2π rad / rev) =  31.42 rad / s

<span>Vt = 0.24(31.42) = 7.5 m/s</span>
3 0
3 years ago
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Somewhere in the vast flat tundra of planet Tehar, a projectile is launched from the ground at an angle of 60 degrees. It reache
Nina [5.8K]

Answer:

R = 0.0503 m

Explanation:

This is a projectile launching exercise, to find the range we can use the equation

       R = v₀² sin 2θ / g

How we know the maximum height

      v_{f}² =v_{oy}² - 2 g y

      v_{f}= 0

      v_{oy} = √ 2 g y

      v_{oy} = √ 2 9.8 / 15

      v_{oy} = 1.14 m / s

Let's use trigonometry to find the speed

    sin θ = v_{oy} / vo

    vo = v_{oy} / sin θ

    vo = 1.14 / sin 60

    vo = 1.32 m / s

We calculate the range with the first equation

     R = 1.32² sin(2 60) / 30

    R = 0.0503 m

3 0
3 years ago
A defibrillator passes 14.0 A of current through the torso of a person for 0.0300 s. How much charge moves in coulombs?
krek1111 [17]
<h2>Answer:</h2>

4.2 C

<h2>Explanation:</h2>

The charge (Q) moving is the product of the current(I) flowing through the torso of the person and the time taken (t) for the flow.

i.e

Q = I x t

Where;

I = current = 14.0A

t = time taken  = 0.0300s

Substituting the values of I and t into the equation above gives

Q = 14.0 x 0.0300

Q = 4.2 C

Therefore quantity of charge moving is 4.2 C

4 0
3 years ago
A uniform electric field is directed parallel to the +y axis. If a positive test charge begins at the origin and moves upward al
lukranit [14]

Answer: option 1 : the electric potential will decrease with an increase in y

Explanation: The electric potential (V) is related to distance (in this case y) by the formulae below

V = kq/y

Where k = 1/4πε0

Where V = electric potential,

k = electric constant = 9×10^9,

y = distance of potential relative to a reference point, ε0 = permittivity of free space

q = magnitude of electronic charge = 1.609×10^-19 c

From the formulae, we can see that q and k are constants, only potential (V) and distance (y) are variables.

We have that

V = k/y

We see the potential(V) is inversely proportional to distance (y).

This implies that an increase in distance results to a decreasing potential and a decrease in distance results to an increase in potential.

This fact makes option 1 the correct answer

3 0
3 years ago
A technician is checking refrigerant system pressures. Both high- and low-side service ports are located on the A/C compressor.
konstantin123 [22]

Answer:

Two major causes are outline bellow

1. The presence of air in the system

2. Clogged condenser

Explanation:

1. The presence of air in the system

One of the causes that have been established in relation to high compressor discharge pressure is the presence of air in the system. When this takes place, your best solution is to recharge the system.

2. Clogged condenser

Another is a clogged condenser in which case you will need to clean the condenser so that it will function properly. When you happen to spot that the discharge valve is closed and it is causing high discharge pressure on the compressor, you can solve that easily by opening the valve

5 0
3 years ago
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