Answer:
Less than.
Explanation:
We have the positive charged metal sphere and we have to determine the electric field at a point near to it. In order to find that if we bring the positive test charge at that point then as we know that "like charges repel" so their electric field lines will repel each other resulting in a weaker electric field.
However if we bring the negative test charge at that point then of course there will be attraction and also the the electric field lines will direct from the positive to negative resulting in a stronger electric field between them. So there will be larger electric field then before.
"In this case, It can be concluded that electric field will be less than it was at this point before the test charge was present."
The following scenarios that accurately describes a
condition in which resonance can occur is vibrating tuning fork is struck and
begins to vibrate as the object used to strike it is placed away from the
tuning fork. The answer is letter B.
Answer:
Kepler's Third Law
T = 2 π r 3 G M E . T = 2 π r 3 G M E . For an ellipse, recall that the semi-major axis is one-half the sum of the perihelion and the aphelion. For a circular orbit, the semi-major axis (a) is the same as the radius for the orbit.
Answer:
The answer is A) 160 Meters.
Explanation:
To determine the distance (d) traveled by a body given its speed (S) and the time (t). Use the equation,
S = d / t ; d = S x t
Substituting the known values to the equation,
d = (4 m/s ) x (40 s) = 160 m
Thus, the person will travel 160 meters in 40 seconds.