Answer:
S=0.6
Step-by-step explanation:
Hope I helped you
Let S=shortest side of the isosceles triangle.
Then length of the congruent sides are both S+1 units.
The perimeter is therefore the sum of all three sides
= S+(S+1)+(S+1)
=3S+2
Side length of square = S-2
Perimeter of square = 4(S-2) = 4S-8
Since the perimeter of square is the same as perimeter of isosceles triangle, we write
4S-8=3S+2
Isolate S and solve
4S-3S=2+8
S=10
Ans. the shortest length of the isosceles triangle is 10 units.
The Least Common Denominator of the two. Ok, first list out multiples of each. 12,24,36,48
16,32,48
Both of them match at 48. That is the answer.
Answer:
x = 7 , y = 37
Step-by-step explanation:
For Δ LMN ≅ Δ PQR
Then corresponding angles must be congruent, that is
∠ P = ∠ L , substitute values
9x - 18 = 5x + 10 ( subtract 5x from both sides )
4x - 18 = 10 ( add 18 to both sides )
4x = 28 ( divide both sides by 4 )
x = 7
Then
∠ P = 9x - 18 = 9(7) - 18 = 63 - 18 = 45°
∠ R = 180° - (84 + 45)° ← sum of angles in a triangle = 180°
∠ R = 180° - 129° = 51°
Then ∠ N = ∠ R
2x + y = 51
2(7) + y = 51
14 + y = 51 ( subtract 14 from both sides )
y = 37
Since the stadium is 6 mi from the practice field which is itself 1 mi from the house, it can either be (1+6)=7 mi North or (1-6)=-5 -> 5 mi South depending on the North/South direction.
the answer is thus A