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Elenna [48]
1 year ago
6

The magnitude of electrical force between a pair of charged particles is ____ as much when the particles are moved half as far a

part.
Physics
1 answer:
Gnesinka [82]1 year ago
8 0

The magnitude of the electrical force between a pair of charged particles is 4 Times as much when the particles are moved half as far apart.

This can be easily understood by Columb's law,

F_{new} = \frac{kQ_{1}Q_{2}}{r^{2}}

which state's that the amount of electrical force experienced by two charged particles is inversely proportional to the square of the distance between them.

∴ \frac{F_{new} }{F_{old} } = \frac{Distance_{new}^{2}  }{Distance_{old}^{2}  }

Now, we know the new distance is half the original distance,

F_{new} = \frac{kQ_{1}Q_{2}}{\frac{r}{2}^{2} } \\F_{new} = 4\frac{kQ_{1}Q_{2}}{r^{2}}

F_{new} = 4F_{old}

The electrical force of attraction or electrostatic force of attraction between two charged particles refers to the amount of attractive or repulsive force that exists between the two charges. This can be calculated by Columb's Law.

A charged particle in physics is a particle that has an electric charge. It might be an ion, such as a molecule or atom having an excess or shortage of electrons in comparison to protons. The same charge is thought to be shared by an electron, a proton, or another primary particle.

Learn more about electrical force here

brainly.com/question/2526815

#SPJ4

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In an earthquake the point where a fault first slips is called the ?
marysya [2.9K]
Slip fault should be
8 0
3 years ago
Kyle has a mass of 54 kg and is jogging at a velocity of 3 m/s. What is Kyle’s kinetic energy?
olga nikolaevna [1]

Answer:243joules

Explanation:

Mass(m)=54kg

Velocity(v)=3m/s

Kinetic energy =(m x v^2)/2

Kinetic energy =(54 x 3^2)/2

Kinetic energy =(54 x 9)/2

Kinetic energy =486/2

Kinetic energy =243joules

8 0
3 years ago
Read 2 more answers
Kinetic energy and mass are ________ proportional.
omeli [17]

Answer:

The Kinetic energy and mass are _directly_ proportional.

Explanation:

We know that Kinetic Energy is basically termed as the capacity of a body to do work.

Kinetic energy is often used to associate with moving objects, therefore, K.E is normally termed as the energy of motion.

The formula of K.E of an object of mass and velocity is defined

K.E = 1/2mv²

From the formula, it is clear that K.E is directly proportional to its mass and also directly proportional to the square of its velocity.

For example,

If A toy plane with a mass of 10 kg is flying at 20 m/s. Its K.E will be:

  • m = 10 kg
  • v = 20 m/s

K.E = 1/2mv²

      = 1/2(10)(20)²

      = 1/2(10)(400)

       = 5(400)

      = 2000 J

Now, let suppose, if we double the mass of a toy plane i.e.

m = 20 kg

so

K.E = 1/2mv²

      = 1/2(20)(20)²

      = 1/2(20)(400)

      = 10(400)

      = 400 J

Therefore, the K.E is doubled when doubled the mass.

Therefore, the Kinetic energy and mass are _directly_ proportional.

9 0
2 years ago
Read 2 more answers
A solid sphere of radius 40.0cm has a total positive charge of 26.0μC uniformly distributed throughout its volume. Calculate the
Rudiy27

The magnitude of the electric field for 60 cm is 6.49 × 10^5 N/C

R(radius of the solid sphere)=(60cm)( 1m /100cm)=0.6m

Q\;(\text{total charge of the solid sphere})=(26\;\mathrm{\mu C})\left(\dfrac{1\;\mathrm{C}}{10^6\;\mathrm{\mu C}} \right)={26\times 10^{-6}\;\mathrm{C}}

Since the Gaussian sphere of radius r>R encloses all the charge of the sphere similar to the situation in part (c), we can use Equation (6) to find the magnitude of the electric field:

E=\dfrac{Q}{4\pi\epsilon_0 r^2}

Substitute numerical values:

E&=\dfrac{24\times 10^{-6}}{4\pi (8.8542\times 10^{-12})(0.6)}\\ &={6.49\times 10^5\;\mathrm{N/C}\;\text{directed radially outward}}}

The spherical Gaussian surface is chosen so that it is concentric with the charge distribution.

As an example, consider a charged spherical shell S of negligible thickness, with a uniformly distributed charge Q and radius R. We can use Gauss's law to find the magnitude of the resultant electric field E at a distance r from the center of the charged shell. It is immediately apparent that for a spherical Gaussian surface of radius r < R the enclosed charge is zero: hence the net flux is zero and the magnitude of the electric field on the Gaussian surface is also 0 (by letting QA = 0 in Gauss's law, where QA is the charge enclosed by the Gaussian surface).

Learn more about Gaussian sphere here:

brainly.com/question/2004529

#SPJ4

6 0
1 year ago
ASAP pls answer right if can’t see picture don’t answer
Anna35 [415]

Answer:

Not sure but

F = m* a

32= 5 * a

a= 6.4 m/s^2

6 0
3 years ago
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