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Ostrovityanka [42]
3 years ago
15

A self-serve frozen yogurt store sells servings up to 12 ounces. It charges $0.50 per ounce for a serving between 0 and 8 ounces

, and $4 for any serving greater than 8 ounces and up to 12 ounces.

Mathematics
1 answer:
barxatty [35]3 years ago
3 0

Answer:The answer is graph B.

Step-by-step explanation: It keeps going up at 0.50 because that is the price PER OUNCE for a serving between 0-8 ounces. The line on the graph is going straight at 4 because that is the price for ANY SERVING over 8 ounces/up to 12 ounces.

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Ksivusya [100]

so you multiply 6 and 3 and it is 18

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Write an equation of a line that is perpendicular to the line y=2/3x and passes through origin
sesenic [268]

keeping in mind that perpendicular lines have negative reciprocal slopes, hmmm what's the slope of the equation above anyway?

\bf y = \cfrac{2}{3}x\implies y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{2}{3}}x+0\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill

\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{2}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{3}{2}}\qquad \stackrel{negative~reciprocal}{-\cfrac{3}{2}}}

so we're really looking for the equation of a line whose slope is -3/2 and runs through (0,0).

\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{0})~\hspace{10em} \stackrel{slope}{m}\implies -\cfrac{3}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{3}{2}}(x-\stackrel{x_1}{0})\implies y=-\cfrac{3}{2}x

7 0
3 years ago
Divide 28 cans of soda into two groups so the ratio is 3 to 4<br>to
Brums [2.3K]
28 = 3x+4x 
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6 0
3 years ago
Why does (x-2)^2+9=0 have no real solutions?
alex41 [277]

Answer:

see explanation

Step-by-step explanation:

Given

(x - 2)² + 9 = 0 ( subtract 9 from both sides )

(x - 2)² = - 9  ( take the square root of both sides )

x - 2 = ± \sqrt{-9}

\sqrt{-9} yields no real solutions

There is no real number when multiplied by itself gives - 9

In fact the solutions to \sqrt{-9} are said to be imaginary, that is ± 3i

where i = \sqrt{-1}

If interested investigate further.

7 0
3 years ago
Use the distributive property to solve the equation -4(x+3)=8
algol [13]

Answer:

x=-5

Step-by-step explanation:

-4(x+3)=8\\\\(-4)(x)+(-4)(3)=8\\\\-4x+(-12)=8\\\\-4x-12=8\\\\-4x-12+12=8+12\\\\-4x=20\\\\\frac{-4x}{-4}=\frac{20}{-4}\\\\x=-5

7 0
2 years ago
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