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aliya0001 [1]
2 years ago
11

How many moles of solute are present in 150mL of 0.30 mol/L NaOH solution ourse

Chemistry
1 answer:
Y_Kistochka [10]2 years ago
6 0

Answer:

0.045 moles of NaOH

Explanation:

When this units are together mol/L, we talk about M, molarity.

This kind of concentration shows the relation between moles of solute which are contained in 1L of solution.

In this case, our NaOH solution is 0.30 M

M = mol/L

Then, M . L = mol

We convert volume to L → 150 mL . 1L /1000 mL = 0.150L

0.150 L . 0.30mol/L = 0.045 moles

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Please help me with chemistry
vodka [1.7K]

Table Giving Answer

Element Atomic mass % Amount

Mg_24     24                79    18.96

Mg_25 25                10    2.5

Mg_26 26                11   2.86

   

Total                     24.32

Discussion

The method of calculation for this table, which was done in Excel (a spread sheet) is shown below. Assume that there is 100 grams of material of "pure" magnesium. What is it's mass?

<em><u>Sample  Calculation</u></em>

The the sample atomic mass = 24

Mass = % * sample atomic mass

Mass = 79% * 24

Mass = (79/100) * 24

Mass = 18.96

<em><u>Note</u></em>

The other two elements are found exactly the same as the sample calculation.

Then all you do is add the 3 masses together.

Answer

The mass of Mg to 1 decimal place is 24.3 <<<< Answer.


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3 years ago
A hydrate of CoCl2 has a mass of 17.40 g before heating. After heating, the mass of the anhydrous compound is found to be 10.27
melisa1 [442]

Mass CoCl2 = 10.27 g
moles CoCl2 = 10.27 g/ 129.839 g/mol=0.07910

mass water = 17.40 - 10.27=7.13 g
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0.396/ 0.07910=5

CoCl2 * 5 H2O

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moles Ca = 1.10
mass Ca = 1.10 x 40.078 g/mol=44.1 g
V = 44.1 / 1.55 =28.5 mL

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Explanation:

7 0
3 years ago
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