All categories

2 years ago

How many moles of solute are present in 150mL of 0.30 mol/L NaOH solution ourse

Chemistry

1 answer:

Y_Kistochka [10]2 years ago

6 0

Answer:

0.045 moles of NaOH

Explanation:

When this units are together mol/L, we talk about M, molarity.

This kind of concentration shows the relation between moles of solute which are contained in 1L of solution.

In this case, our NaOH solution is 0.30 M

M = mol/L

Then, M . L = mol

We convert volume to L → 150 mL . 1L /1000 mL = 0.150L

0.150 L . 0.30mol/L = 0.045 moles

You might be interested in

What does a horizontal row of elements in the periodic table represents

xxTIMURxx [149]

The periods or energy levels

8 0

3 years ago

Read 2 more answers

Paano mag ka jowa? any suggestions?

melamori03 [73]

Well just wait for the right time to come, Because if you wait for the right time, you're gonna find someone who you really want- I'm bad at understanding tagalog

6 0

3 years ago

Read 2 more answers

Hãy chỉ tôi hoá học. Tôi không thể viết nhưng tôi có bức ảnh

Digiron [165]

Answer:

what can you speak English

8 0

3 years ago

What is the mass of solute in a 500 mL solution of 0.200 M

Fofino [41]

16.4 grams is the mass of solute in a 500 mL solution of 0.200 M .

sodium phosphate

Explanation:

Given data about sodium phosphate

atomic mass of Na3PO4 = 164 grams/mole

volume of the solution = 500 ml or 0.5 litres

molarity of sodium phosphate solution = 0.200 M

The formula for molarity will be used here to know the mass dissolved in the given volume of the solution:

The formula is

molarity = $\frac{number of moles of solute}{volume in litres}$

putting the values in the equation, we get

molarity x volume = number of moles

0.200 X 0.5= number of moles

number of moles = 0.1 moles

Atomic mass x number of moles = mass

putting the values in the above equation

164 x 0.1 = 16.4 grams

16.4 grams of sodium phosphate is present in 0.5 L of the solution to make a 0.2 M solution.

8 0

3 years ago

How many atoms are there in 8.88 g Si?

Mariana [72]

Answer:

$\boxed {\boxed {\sf 1.90 \times 10^{23} \ atoms \ Si}}$

Explanation:

We are asked to find how many atoms are in 8.88 grams of silicon.

<h3>1. Grams to Moles </h3>

First, we convert grams to moles. We use the molar mass or the mass of 1 mole of a substance. These values are found on the Periodic Table as they are equal to the atomic masses, but the units are grams per mole instead of atomic mass units.

Look up silicon's molar mass.

Si: 28.085 g/mol

We will convert using dimensional analysis. Set up a conversion factor with the molar mass.

$\frac { 28.085 \ g \ Si}{1 \ mol \ Si}$

We are converting 8.88 grams of silicon to moles, so we multiply by this value.

$8.88 \ g \ Si *\frac { 28.085 \ g \ Si}{1 \ mol \ Si}$

Flip the fraction so the units of grams of silicon cancel.

$8.88 \ g \ Si *\frac{1 \ mol \ Si} { 28.085 \ g \ Si}$

$8.88 *\frac{1 \ mol \ Si} { 28.085 }$

$\frac {8.88} { 28.085 } \ mol \ Si$

$0.316183015845 \ mol \ Si$

<h3>2. Moles to Atoms </h3>

Next, we convert moles to atoms. We use Avogadro's Number or 6.022 × 10²³. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance. In this case, the particles are atoms of silicon.

Set up another conversion factor.

$\frac {6.022 \times 10^{23} \ atoms \ Si}{1 \ mol \ Si}$