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aliya0001 [1]
3 years ago
11

How many moles of solute are present in 150mL of 0.30 mol/L NaOH solution ourse

Chemistry
1 answer:
Y_Kistochka [10]3 years ago
6 0

Answer:

0.045 moles of NaOH

Explanation:

When this units are together mol/L, we talk about M, molarity.

This kind of concentration shows the relation between moles of solute which are contained in 1L of solution.

In this case, our NaOH solution is 0.30 M

M = mol/L

Then, M . L = mol

We convert volume to L → 150 mL . 1L /1000 mL = 0.150L

0.150 L . 0.30mol/L = 0.045 moles

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ankoles [38]
Strong acid:dissolves and dissociates 1005 to produce protons (H+) 1. seven
strong acids: HCI, HBr, HI, HNO3, H2SO4, and HCIO3. ...
weak acid: dissolves but less than 100% dissociates to produce protons (H+) 1.
3 0
3 years ago
An amphoteric salt is one that contains an anion that can act as either an acid or a base in water. Baking soda, NaHCO3, is an e
LenKa [72]

Answer:

pH = 8.34

Explanation:

The equilbriums of the amphoteric HCO₃⁻ (Ion of NaHCO₃) are:

H₂CO₃ ⇄ <em>HCO₃⁻</em> + H⁺ Ka1 <em>-Here, HCO₃⁻ is acting as a base-</em>

<em>HCO₃⁻</em>⇄ CO₃²⁻ + H⁺ Ka2 <em>-Here, is acting as an acid-</em>

Where Ka1 = 4.3x10⁻⁷ and Ka2 = 4.8x10⁻¹¹. As pKa = -log Ka:

pKa1 = 6.37; pKa2 = 10.32

As the pH of amphoteric salts is:

pH = (pKa1 + pKa2) / 2

<h2>pH = 8.34</h2>
3 0
3 years ago
A ph of 2 indicates a
alekssr [168]
Nope mate I have no clue
5 0
3 years ago
A 25.0 mLsample of an acetic acid solution is titrated with a 0.175 M NaOH solution. The equivalence point is reached when 37.5
matrenka [14]

Answer:

0.263M of CH₃COOH is the concentration of the solution.

Explanation:

The reaction of acetic acid (CH₃COOH) with NaOH is:

CH₃COOH + NaOH → CH₃COO⁻Na⁺ + H₂O

<em>1 mole of acetic acid reacts per mole of NaOH to produce sodium acetate and water.</em>

<em />

In the equivalence point, moles of acetic acid are equal to moles of NaOH and moles of NaOH are:

0.0375L × (0.175 moles / L) = 6.56x10⁻³ moles of NaOH = moles of CH₃COOH.

As the sample of acetic acid had a volume of 25.0mL = 0.025L:

6.56x10⁻³ moles of CH₃COOH / 0.0250L =

<em>0.263M of CH₃COOH is the concentration of the solution</em>

3 0
3 years ago
What is the pOH of a solution that has a hydronium ion concentration [H3O+] of 8.26 x 10–5 M
viva [34]

Answer:

The pOH of the solution is 9.92

Explanation:

pH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance. PH is defined as the negative logarithm (base 10) of the hydronium ion concentration [H₃O⁺]:

pH= - log [H₃O⁺]

So, if [H₃O⁺]=8.26*10⁻⁵, the pH is: pH=- log (8.26*10⁻⁵) ⇒ pH= 4.08

The pOH measures the concentration of OH− ions. The following relationship can be established between pH and pOH:

pH + pOH= 14

In this case, being pH=4.08  and replacing in the relationship between pH and pOH:

4.08 + pOH=14

Solving:

pOH= 14 - 4.08

pOH= 9.92

The pOH of the solution is 9.92

6 0
3 years ago
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