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3 years ago

How many moles of solute are present in 150mL of 0.30 mol/L NaOH solution ourse

Chemistry

1 answer:

Y_Kistochka [10]3 years ago

6 0

Answer:

0.045 moles of NaOH

Explanation:

When this units are together mol/L, we talk about M, molarity.

This kind of concentration shows the relation between moles of solute which are contained in 1L of solution.

In this case, our NaOH solution is 0.30 M

M = mol/L

Then, M . L = mol

We convert volume to L → 150 mL . 1L /1000 mL = 0.150L

0.150 L . 0.30mol/L = 0.045 moles

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Which of the following is the correct unit for molarity? mol/L L/mol g/mol mol × L

Tems11 [23]

mol/L

Molarity indicates the number of moles of solute per liter of solution.

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3 years ago

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Mr. Ragusa asks Hassan to make silver crystals from the following reaction.

SVEN [57.7K]

Answer:

Percentage yield = 61.7%

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated:

2AgNO₃ + Cu —> Cu(NO₃)₂ + 2Ag

Next, we shall determine the mass of AgNO₃ that reacted and the mass of Ag produced from the balanced equation. This is illustrated below:

Molar mass of AgNO₃ = 108 + 14 + (16×3)

= 108 + 14 + 48

= 170 g/mol

Mass of AgNO₃ from the balanced equation = 2 × 170 = 340 g

Molar mass of Ag = 108 g/mol

Mass of Ag from the balanced equation = 2 × 108 = 216 g

SUMMARY:

From the balanced equation above,

340 g of AgNO₃ reacted to produce 216 g of Ag.

Next, we shall determine the theoretical yield of Ag. This can be obtained as follow:

From the balanced equation above,

340 g of AgNO₃ reacted to produce 216 g of Ag.

Therefore, 51 g of AgNO₃ will react to produce = (51 × 216)/340 = 32.4 g of Ag.

Thus, the theoretical yield of Ag is 32.4 g.

Finally, we shall determine the percentage yield of Ag. This can be obtained as follow:

Actual yield = 20 g

Theoretical yield = 32.4 g

Percentage yield =?

Percentage yield = Actual yield /Theoretical yield × 100

Percentage yield = 20 / 32.4 × 100

Percentage yield = 61.7%

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3 years ago

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Nataliya [291]

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3 years ago

Sucrose is a non volatile, non-ionizing solute in water.

Natasha2012 [34]

When a non volatile solute is added to a solvent, the vapor pressure of the solvent will decrease.

Vapor pressure is a colligative property. Which means that it will be affected by the number of particles of solute.

The relationship between the concentration of the solute and the vapor pressure is given by Roult's Law

ΔP = Xsolute * P, where ΔP is vapor pressure lowering, Xsolute is the molar fractionof the solute, and P is the vapor pressure of the solvent.

Then lets find Xsolute

X solute = # moles solute / # moles solution

# moles solute = 75.0 grams / molar mass

molar mass of C12H22O11 = 12*12g/mol + 22*1g/mol + 11*16g/mol = 342 g/mol

# moles solute = 75.0/342 mol = 0.219 mol

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# moles of solvent = 180 grams /18 g/mol = 10 mols

Xsolute = 0.219 mol solute / (10 + 0.219) mol solution =0.0215

ΔP = 0.0215*26.7 torr = 0.57 torr

Answer= 0.57 torr

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3 years ago