What is The pH and pOH of a 1.00x10-3M solution of CH3COOH (Ka=1.75x10-5) ?
1 answer:
Answer:
<h2>pH = 3.9</h2><h2>pOH = 10.1</h2>Explanation:
Since is a weak acid to find the pH of
we use the formula
where
Ka is the acid dissociation constant
c is the concentration
From the question
Ka of = 1.75 × 10^-5
c = 1.00 × 10-³M
Substitute the values into the above formula and solve for the pH
That's
We have the answer as
<h3>pH = 3.9</h3>To find the pOH we use the formula
pH + pOH = 14
pOH = 14 - pH
pOH = 14 - 3.9
We have the answer as
<h3>pOH = 10.1</h3>Hope this helps you
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Explanation:
As it is known that molarity is the number of moles present in a liter of solution.
Mathematically, Molarity =
As it is given that molarity is 0.10 M and volume is 10.0 ml. As 1 ml equals 0.001 L. Therefore, 10.0 ml will also be equal to 0.01 L.
Hence, putting these values into the above formula as follows.
Molarity =
0.10 M =
no. of moles = 0.001 mol
As molar mass of KCN is equal to 65.12 g/mol. Therefore, calculate the mass of KCN as follows.
No. of moles =
0.001 mol =
mass = 0.06152 g
Thus, we can conclude that 0.06152 grams of KCN are in 10.0 ml of a 0.10 M solution.