All categories

3 years ago

A substance is tested and has a pH of 1.2. How would you classify it?

Chemistry

2 answers:

djyliett [7]3 years ago

6 0

Answer:

A weak acid

Explanation:

Im not sure if its right. But lets see someone else do it.

aalyn [17]3 years ago

3 0

Answer:

B. A strong acid.

An electrolyte with a pH less than 4 is a strong acid, that with pH range of 4 - 7 is a weak acid, that with 7 - 10 is a weak base, that with pH range of 10 - 14 is a strong base.

You might be interested in

What is the density of ethane gas, C2H6 at STP

yawa3891 [41]

Answer:

The answer is that ethane gas has a density of 1.34 g/L at STP

Explanation:

Ethane weighs 0.0013562 gram per cubic centimeter or 1.3562 kilogram per cubic meter, i.e. density of ethane is equal to 1.3562 kg/m³; at 0°C (32°F or 273.15K) at standard atmospheric pressure.

7 0

3 years ago

An ideal gas (C}R), flowing at 4 kmol/h, expands isothermally at 475 Kfrom 100 to 50 kPa through a rigid device. If the power pr

Zina [86]

<u>Answer:</u> The rate of heat flow is 3.038 kW and the rate of lost work is 1.038 kW.

<u>Explanation:</u>

We are given:

$C_p=\frac{7}{2}R\\\\T=475K\\P_1=100kPa\\P_2=50kPa$

Rate of flow of ideal gas , n = 4 kmol/hr = $\frac{4\times 1000mol}{3600s}=1.11mol/s$ (Conversion factors used: 1 kmol = 1000 mol; 1 hr = 3600 s)

Power produced = 2000 W = 2 kW (Conversion factor: 1 kW = 1000 W)

We know that:

$\Delta U=0$ (For isothermal process)

So, by applying first law of thermodynamics:

$\Delta U=\Delta q-\Delta W$

$\Delta q=\Delta W$ .......(1)

Now, calculating the work done for isothermal process, we use the equation:

$\Delta W=nRT\ln (\frac{P_1}{P_2})$

where,

$\Delta W$ = change in work done

n = number of moles = 1.11 mol/s

R = Gas constant = 8.314 J/mol.K

T = temperature = 475 K

$P_1$ = initial pressure = 100 kPa

$P_2$ = final pressure = 50 kPa

Putting values in above equation, we get:

$\Delta W=1.11mol/s\times 8.314J\times 475K\times \ln (\frac{100}{50})\\\\\Delta W=3038.45J/s=3.038kJ/s=3.038kW$

Calculating the heat flow, we use equation 1, we get:

[ex]\Delta q=3.038kW[/tex]

Now, calculating the rate of lost work, we use the equation:

$\text{Rate of lost work}=\Delta W-\text{Power produced}\\\\\text{Rate of lost work}=(3.038-2)kW\\\text{Rate of lost work}=1.038kW$

Hence, the rate of heat flow is 3.038 kW and the rate of lost work is 1.038 kW.

4 0

3 years ago

Which will have a greater volume: 10 grams of liquid water or 10 grams of solid water?

san4es73 [151]

The volume of 10 grams of frozen water is more than the volume of 10 grams of liquid water

5 0

3 years ago

What are the names of the following three compounds (see attached)

balu736 [363]

Answer:

1. 4-ethyl-1-heptene

2. 6-ethyl-2-octene

3. 1-butyne

Explanation:

The compounds are named according to IUPAC rules.

Compound 1:

Identify the longest carbon chain. This chain is called the parent chain.
Identify all of the substituents (groups appending from the parent chain).
The parent chain is numbered so that the multiple bonds have the lowest numbers (double has the priority over alkyl substituents).
The longest chain contains 7 carbon atoms, so taken the name hept.
The double bond between C1 and C2, so take no. 1 and add the suffix ene to hept "1-heptene".
The ethyl group is the alkyl substituent on position 4.
So the name is 4-ethyl-1-heptene.

Compound 2:

Identify the longest carbon chain. This chain is called the parent chain.
Identify all of the substituents (groups appending from the parent chain).
The parent chain is numbered so that the multiple bonds have the lowest numbers (double has the priority over alkyl substituents).
The longest chain contains 8 carbon atoms, so taken the name oct.
The double bond between C2 and C3, so take no. 2 and add the suffix ene to oct "2-octene".
The ethyl group is the alkyl substituent on position 6.

So the name is 6-ethyl-2-octene.

Compound 3:

Identify the longest carbon chain. This chain is called the parent chain.
Identify all of the substituents (groups appending from the parent chain), there is no substituents.
The parent chain is numbered so that the multiple bonds have the lowest numbers (Triple bond here take the lowest number).
The longest chain contains 4 carbon atoms, so taken the name but.
The triple bond between C1 and C2, so take no. 1 and add the suffix yne to but "1-butyne".