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2 years ago

13

Tertiary or top consumers are animals at the top of the food web. They may feed off either primary or secondary consumers. What

animals would fit into this classification?

1 answer:

babymother [125]2 years ago

7 0

Answer:

Coyotes, Bald Eagles, & Gray wolf.

You might be interested in

How many atoms of oxygen are in 4.00 moles of N2O5

SVETLANKA909090 [29]

Answer:

there are 20 oxygen atoms in 4.00 moles of Dinitrogen pentoxide

Explanation:

there are 2 atoms in an oxygen molecule , so each oxygen molecules has at least 2. Dinitrogen pentoxide is N2O5, which has 7 atoms, 2 nitrogen and 5 oxygen. 1 molecule of N2O5 has 5 oxygen atoms, so 4 of then would be 20

8 0

2 years ago

Using the Lewis dot structures of magnesium and oxygen, predict the ionic formula

Blizzard [7]

Answer:

(edit: nvm I figured it out, here is the answer)

Explanation:

7 0

3 years ago

What is the molecular formula of the hydrocarbon whose molar mass is 536 g/mol and contains 89.55 w/w% carbon?

leonid [27]

Given the percentage composition of HC as C → 81.82 % and H → 18.18 %

So the ratio of number if atoms of C and H in its molecule can will be:

C : H = 81.82 12 : 18.18 1 C : H = 6.82 : 18.18 = 6.82 6.82 : 18.18 6.82 = 1 : 2.66 ≈ 3 : 8

So the Empirical Formula of hydrocarbon is:

C 3 H 8

As the mass of one litre of hydrocarbon is same as that of C O 2 The molar mass of the HC will be same as that of C O 2 i.e 44 g mol

Now let Molecular formula of the HC be ( C 3 H 8 ) n

Using molar mass of C and H the molar mass of the HC from its molecular formula is:

( 3 × 12 + 8 × 1 ) n = 44 n So 44 n = 44 ⇒ n = 1

Hence the molecular formula of HC is C 3 H 8

Does that help?

7 0

3 years ago

The decomposition of acetaldehyde is a second order reaction with a rate constant of 4.71 10−8 L/mol/s. What is the instantaneou

pochemuha

Answer: Rate of decomposition of acetaldehyde in a solution is $1.45\times 10^{-14}mol/Ls$

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

For a reaction : $A\rightarrow products$

$Rate=k[A]^x$

k= rate constant

x = order of the reaction = 2

$Rate=4.71\times 10^{-8}L/mol/s\times {5.55\times 10^{-4}M}^2$

$Rate=1.45\times 10^{-14}$

Thus rate of decomposition of acetaldehyde in a solution is $1.45\times 10^{-14}mol/Ls$

6 0

2 years ago

Consider the reaction. mc014-1.jpg How many grams of methane should be burned in an excess of oxygen at STP to obtain 5.6 L of c

garri49 [273]

The reaction for the combustion of methane can be expressed as follows.
CH4 + 2O2 --> CO2 + 2H2O
We solve first for the amount of carbon dioxide in moles by dividing the given volume by 22.4L which is the volume of 1 mole of gas at STP.
moles of CO2 = (5.6 L) / (22.4 L/1 mole)
moles of CO2 = 0.25 moles
Then, we can see that every mole of carbon dioxide will need 1 mole of methane
moles methane = (0.25 moles CO2) x (1 moles O2/1 mole CO2)
= 0.25 moles CH4
Then, multiply this by the molar mass of methane which is 16 g/mole. Thus, the answer is 4 grams methane.

5 0

3 years ago

Read 2 more answers