Since this has to do with titration, the measured volume of NaOH used would be less than the actual volume used because some of the unused NaOH would cling to the sides of the buret and therefore wouldn't factor into the measurement
Hope this helps
X=percentage of Cl-35
(1-x)=percentage of Cl-35
35(x)+37(1-x)=35.454
35x+37-37x=35.454
-2x=35.454-37
-2x=-1.546
x=-1.546/(-2)
x=0.773
0.773=77.3/100=77.3%
(1-x)=1-0.773=0.227
0.227=22.7/100=22.7%
answer: the percentages are: 77.3% of Cl-35 and 22.7% of Cl-37.
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