Answer : The value of change in entropy for freezing process is, -18.07 J/mol.K
Explanation :
Formula used :

where,
= change in entropy
= change in enthalpy of fusion = 3.17 kJ/mol
As we know that:

= freezing point temperature = 
Now put all the given values in the above formula, we get:



Therefore, the value of change in entropy for freezing process is, -18.07 J/mol.K
Answer:
A) pH of Buffer solution = 4.59
B) pH after 5.0 ml of 2.0 M NaOH have been added to 400 ml of the original buffer solution = 4.65
Explanation:
This is the Henderson-Hasselbalch Equation:
![pH = pKa + log\frac{[conjugate base]}{[acid]}](https://tex.z-dn.net/?f=pH%20%3D%20pKa%20%2B%20log%5Cfrac%7B%5Bconjugate%20base%5D%7D%7B%5Bacid%5D%7D)
to calculate the pH of the following Buffer solutions.
Answer:
deposition
Explanation:
Sublmation- solid transforming into a gas, skipping the liquid stage.
eveporation- a liquid transformimg into a gas
melting- a solid transforming into a liquid
deposition- the opposite of sublimation (your anwser)
First and foremost, they are completely different substances with each exhibiting unique properties. Both have different atoms involved on their structures which is the cause of the differing properties.