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2 years ago

If a car travels 800m in 30 seconds how fast is it going? HELP MEEE!!

Chemistry

1 answer:

Paul [167]2 years ago

7 0

Answer:

Explanation:

The speed of the car can be found by using the formula

$v = \frac{d}{t} \\$

d is the distance

t is the time taken

From the question we have

$v = \frac{800}{30} = \frac{80}{3} \\ = 26.66666...$

We have the final answer as

Hope this helps you

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What is the percent composition of nitrogen in N 2 O

mash [69]

Answer:

63.6%

Explanation:

The given compound is:

N₂O;

The problem here is to find the percent composition of nitrogen in the compound.

First find the molar mass of the compound:

Molar mass of N₂O = 2(14) + 16 = 44g/mol

So;

Percentage composition of Nitrogen = $\frac{2 x 14}{44}$ x 100 = 63.6%

5 0

2 years ago

lucose, a major energy-yielding nutrient, is present in bacterial cells at a concentration of approximately 0.200 mM. i) What is

Mkey [24]

Answer:

The concentration is 0.036 mg/mL

Explanation:

Concentration = 0.2 mM = 0.2/1000 = 2×10^-4 M = 2×10^-4 mol/L × 180,000 mg/1 mol × 1 L/1000 mL = 0.036 mg/mL

3 0

2 years ago

cuantos electrones se necesitan para formar una carga -38uC sabiendo que la carga de un solo electrón es -1.6×10-19 C???

Over [174]

No te entiendo corazón......

4 0

2 years ago

You have come down with a nasty cold and would like to understand why the virus that infected you is making you feel so lousy. W

umka21 [38]

Answer:

a) The volume is 5.236x10⁻¹³L

b) The molarity of a single virus is 1.91x10¹² mol/L

c) The molarity for a 100 virus particles is 1.91x10¹⁴ mol/L

Explanation:

a) Given:

D = diameter of the cell = 10 μm

r = radius = 10/2 = 5 μm

The volume of the spherical cell is equal:

$V=\frac{4}{3} \pi r^{3} =\frac{4}{3} \pi *(5)^{3} =523.6\mu m^{3}$

If 1 μm³ = 1x10⁻¹⁵L, then 523.6 μm³ = 5.236x10⁻¹³L

b) The molarity is:

$M=\frac{number-of-moles}{volume-of-solution}$

For a single virus within the cell

$M=\frac{1}{5.236x10^{-13} } =1.91x10^{12} mol/L$

c) For a 100 virus particles the molarity is:

$M=\frac{100}{5.236x10^{-13} } =1.91x10^{14} mol/L$

4 0

2 years ago

___au2s3 ___h2 → ___au ___h2s

liberstina [14]

The best way to balance an equation is to balance one atom at a time.
You start with two Au atoms on the left, so you know the coefficient of Au on the right has to be 2. So at first we get,
Au2S3 + H2 --> 2Au + H2S
Then, notice you have 3 sulfur atoms on the left, so you need three on the right.
Our equation becomes
Au2S3 + H2 --> 2Au + 3H2S
Lastly, we now have six hydrogen atoms on the right, and only two on the left, so we assign a three to the H2 on the left
Au2S3 + 3H2 --> 2Au + 3H2S Is the balanced final equation.

7 0

2 years ago