Answer:
548 g/mol
Explanation:
The freezing point depression of a solvent occurs when a nonvolatile solute is added to it. Because of the interactions between solute-solvent, it is more difficult to break the bonds, so the phase change will need more energy, and the freezing point will drop, which is called cryoscopy.
The drop in temperature can be calculated by:
ΔT = Kf*W*i
Where Kf is the cryoscopy constant of the solvent, W is the molality, and i is the van't Hoff factor, which indicates the fraction of the solute that dissolves.
The molality represents how much moles (n) of the solute is presented in each kg of the solvent (m2), thus
W = n/m2
The number of moles is the mass of the solute (m1) in g, divided by the molar mass (M1) of it:
W = m1/(M1*m2)
So, by the data:
0.2214 = 0.632/(M1*0.00521)
0.00115M1 = 0.632
M1 = 548 g/mol
Answer:
2.5 moles of H2
Explanation:
First, let us write a balanced equation for the reaction of Hydrogen to produce water. This is shown below:
2H2 + O2 —> 2H2O
From the equation above,
2 moles of H2 produced 2 moles of H2O.
Therefore, 2.5 moles of H2 will produce 2.5 moles of H2O
Answer:
Bromine and mercury are liquid at room temperature and gallium is liquid when just a little above room temperature. Originally Answered: What are the only two elements that are liquid at 25° C (room temperature)? Mercury and Bromine. Mercury is solid below -38 degrees F (-39C) and Bromine below 19 degrees F (-7.2C).
Explanation:
The molar mass of Al₂(CO₃)₃is 233.99 g/mol
<span>It means 233.99 grams of Al</span>₂(CO₃)₃ are in one mole
And moles in 47.6 g = 47.6/233.99 = 0.203 moles
Now we know that we have 0.203 moles of Al₂(CO₃)₃
In one mole of Al₂(CO₃)₃, we have 3 moles of carbon
To find the number of moles of carbon in a 0.203 moles of Al₂(CO₃)₃, we
must multiply this by the 3 moles of carbon <span>
0.203 x 3 = 0.609 moles of carbon
Within one mole of carbon, we have 6.022 x 10</span>²³ atoms. So, to find the amount of atoms within 0.609 moles of carbon, we must
multiply the 0.609 moles by 6.022 x 10²³ atoms.
<span>
<span>So, the number of carbon atoms present in 47.6g of
Al</span></span>₂(CO₃)₃ = 0.609 x 6.022 x 10²³ = 3.667 x 10²³ atoms.
Answer:
A. A solid mixture is heated. One component transitions directly between solid and gas ---> Sublimation
B. A liquid is carefully poured out, leaving the solid behind in the container ----> Decantation
C. A solvent is added to dissolve only one mixture component and then the liquids are separated ----> solvent extraction
D. A solid is caught on paper or a membrane while the liquid passes through ---> Filtration using filter paper
Explanation:
A. Sublimation is a process of separating solids which sublimes (solids turning directly to gases) from a a mixture of other solids which do not sublime. When the mixture is heated, the solids which sublime are separated and those which do not are left behind. examples of solids which sublime are naphthalene, Iodine crystals, etc.
B. Decantation is the process of carefully pouring out a liquid from a mixture of it with a solid, leaving the solid behind. Example, a mixture of sand and water where water can be easily decanted, leaving the sand behind.
C. In the process of solvent extraction, a mixture of solids which are soluble in different solvent, one of the components is dissolved in a solvent in which it is soluble while the others are not. The solution is then filtered out and the solid is then separated from the solvent by evaporation.
D. In filtration using a filter paper, the solid-liquid mixture is passed through a filter paper which has pores the size through which liquids can pass through but the solid can not. therefore, the solid remains behind on the paper while the liquid passes through.