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marusya05 [52]
3 years ago
13

A small hot-air balloon is filled with 1.02×106 l of air (d = 1.20 g/l). as the air in the balloon is heated, it expands to 1.09

×106 l. what is the density of the heated air in the balloon?
Physics
2 answers:
liberstina [14]3 years ago
7 0
The first thing you should know for this case is that density is defined as the quotient between mass and volume.
 d = m / v
 We have two states:
 State 1:
 d1 = 1.20 g / l
 v1 = 1.02 × 106 l
 State 2:
 v2 = 1.09 × 106 l
 Since the mass remains constant, then:
 m = d1 * v1
 Then, the density in state two will be:
 d2 = m / v2
 Substituting the value of the mass we have:
 d2 = (d1 * v1) / v2
 Substituting the values:
 d2 = ((1.20) * (1.02 * 10 ^ 6)) / (1.09 * 10 ^ 6) = 1.12 g / l
 answer:
 The density of the heated air in the balloon is 1.12 g / l
Lelechka [254]3 years ago
6 0
1.12 g/L  
The total mass of the air will remain constant, but since the volume changes and density is defined as mass per volume, we can simply calculate the new density of the heated air.  
variables 
d0, d1 = density cold, density hot
 m = mass of air
 v0, v1 = volume cold, volume hot 
 d0 = m/v0 = 1.20 g/L
 d1 = m/v1 
 m/v0 = 1.20 g/L
 m = v0 * 1.20 g/L
 m/v1 = v0 * 1.20 g/L / v1
 d1 = v0 * 1.20 g/L / v1 
 d1 = 1.02x10^6 * 1.20 g/L / 1.09x10^6
 d1 = 1.02x10^6 * 1.20 g/L / 1.09x10^6
 d1 = 1.12 g/L 
 So the density of the heated air is 1.12 g/L

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1. Determination of the distance travelled.

Distance 1 (d₁) = 7 km

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Total distance (dₜ) =?

dₜ = d₁ + d₂

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dₜ = 12 km

2. Determination of the displacement.

In the attached photo, R is the displacement.

We can obtain the value of R by using the pythagoras theory as illustrated below:

R² = 7² + 5²

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nadezda [96]

Answer:

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Given the description of period and amplitude, the SHM could be described by:

f(x)=5\,sin(\frac{\pi}{4}x)

and its angular velocity can be calculated doing the derivative:

f(x)=5\, \,sin(\frac{\pi}{4}x)\\f'(x)=5\,\frac{\pi}{4}\,cos(\frac{\pi}{4}x)

And therefore, the tangential velocity is calculated by multiplying this expression times the radius of the movement (3 m):

velocity(x)=15\,\frac{\pi}{4}\,cos(\frac{\pi}{4}x)  and is given in m/s.

Then the maximum speed is obtained when the cosine function becomes "1", and that gives:

Max speed = \frac{15\, \pi}{4} \,\, \frac{m}{s}

The acceleration is found from the derivative of the velocity expression, and therefore given by:

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