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stiv31 [10]
4 years ago
10

A forcue of 186 N acts on a 7.3-kg bowling ball for 0.40 s. what is the chanhe in velocity of the bowling ball

Physics
2 answers:
baherus [9]4 years ago
3 0

As we know that Force = mass * acceleration.   
Here a force of 186 N acting on 7.3 kg ball will create acceleration = 186/7.3 = 25.48 m/s2  
Also, change in velocity can be found as, acceleration multiplied by time it is acting on object. 
Therefore, change in velocity = 24.48 * 0.4 = 10.19 m/s
motikmotik4 years ago
3 0
Given are: Force = 186 N; Mass = 7.3 Kg; time = 0.40 s Initial Velocity Vi = 0
Final Velocity Vf = ?
Unknown: Change in velocity or acceleration 
F =ma;  but a = Vf - Vi/t  Solve for Vf or Final velocity
therefor  F = m(Vf-Vi/t) Ft = m(Vf - Vi/t)   But Vi = 0
Vf = (186 N)(0.40 S)/7.3 Kg  answer Vf = 10.2 m/s
Solving for acceleration or change in velocity
a = Vf - Vi/t
a = 10.2 m/s - 0/0.4s  therefore change in velocity a = 25.5 m/s²



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t = Time taken

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\text{Distance}=20\times 0.5=10\ m

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\text{Distance}=u\times 0.5=0.5u\ m

v^2-u^2=2as\\\Rightarrow -u^2=2as-v^2\\\Rightarrow u^2=v^2-2as\\\Rightarrow u^2=0^2-2\times -10\times (44-0.5u)\\\Rightarrow u^2=20(44-0.5u)\\\Rightarrow u^2=880-10u\\\Rightarrow u^2+10u-880=0

u=\frac{-10+\sqrt{10^2-4\cdot \:1\left(-880\right)}}{2\cdot \:1}, u=\frac{-10-\sqrt{10^2-4\cdot \:1\left(-880\right)}}{2\cdot \:1}\\\Rightarrow u=25.08, -35.08\ m/s

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