98 elements are naturally forming elements.
Answer: 98
Answer:
Demo Mole Quantities
58.5g NaCl(mol/58.5g)(6.02 x 1023/mol) = 6.02 x 1023 Na
+
Cl21 pre-1982 pennies (after 1982 pennies are mostly zinc with copper coating)
63.5g Cu( mol/ 63.5g)(6.02 x 1023/mol) = 6.02 x 1023 Cu
19.0g Al (mol/27.0g)(6.02 x 1023/mol) = 4.24 x 1023 Al
Explanation:
Answer:
The device shown is a calorimeter that used to measure the heat transfer by a reaction under constant volume.
Explanation:
In the exothermic process..
Have a great day!
<u>Answer:</u> The nuclear binding energy of the given element is 
<u>Explanation:</u>
For the given element 
Number of protons = 3
Number of neutrons = (6 - 3) = 3
We are given:

M = mass of nucleus = 
![M=[(3\times 1.00728)+(3\times 1.00866)]=6.04782amu](https://tex.z-dn.net/?f=M%3D%5B%283%5Ctimes%201.00728%29%2B%283%5Ctimes%201.00866%29%5D%3D6.04782amu)
Calculating mass defect of the nucleus:
![\Delta m=M-A\\\Delta m=[6.04782-6.015126)]=0.032694amu=0.032694g/mol](https://tex.z-dn.net/?f=%5CDelta%20m%3DM-A%5C%5C%5CDelta%20m%3D%5B6.04782-6.015126%29%5D%3D0.032694amu%3D0.032694g%2Fmol)
Converting this quantity into kg/mol, we use the conversion factor:
1 kg = 1000 g
So, 
To calculate the nuclear binding energy, we use Einstein equation, which is:

where,
E = Nuclear binding energy = ? J/mol
= Mass defect = 
c = Speed of light = 
Putting values in above equation, we get:

Hence, the nuclear binding energy of the given element is 