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konstantin123 [22]
3 years ago
10

1) A chemist was deciding what chemical to use in a handwarmer. She studies 2 compounds. One is a nonpolar covalent compound tha

t is safe and nontoxic. The other is an ionic compound. It is poisonous if ingested. What tests could she do to tell them apart? Give two possible observations or tests she can run to verify the substance. Which substance would you use to make the handwarmer and why?
Chemistry
1 answer:
Lynna [10]3 years ago
3 0

Answer:     Water dissolves nonpolar covalent  substances.

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How many molecules of H2O are equivalent to 98.2 g of H2O
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Demo Mole Quantities

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Given the following information: Mass of proton = 1.00728 amu Mass of neutron = 1.00866 amu Mass of electron = 5.486 × 10^-4 amu
lesya692 [45]

<u>Answer:</u> The nuclear binding energy of the given element is 2.938\times 10^{12}J/mol

<u>Explanation:</u>

For the given element _3^6\textrm{Li}

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Number of neutrons = (6 - 3) = 3

We are given:

m_p=1.00728amu\\m_n=1.00866amu\\A=6.015126amu

M = mass of nucleus = (n_p\times m_p)+(n_n\times m_n)

M=[(3\times 1.00728)+(3\times 1.00866)]=6.04782amu

Calculating mass defect of the nucleus:

\Delta m=M-A\\\Delta m=[6.04782-6.015126)]=0.032694amu=0.032694g/mol

Converting this quantity into kg/mol, we use the conversion factor:

1 kg = 1000 g

So,  0.032694g/mol=0.032694\times 10^{-3}kg/mol

To calculate the nuclear binding energy, we use Einstein equation, which is:

E=\Delta mc^2

where,

E = Nuclear binding energy = ? J/mol

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c = Speed of light = 2.9979\times 10^8m/s

Putting values in above equation, we get:

E=0.032694\times 10^{-3}kg/mol\times (2.9979\times 10^8m/s)^2\\\\E=2.938\times 10^{12}J/mol

Hence, the nuclear binding energy of the given element is 2.938\times 10^{12}J/mol

3 0
3 years ago
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