Answer:
34.05dm^3 of nitrogen gas
Explanation:
First things first, we need to find the number of moles of Sodium azide. We can do that by using the formula m=nM, mass = no. moles x Molar Mass
Rearrange to solve for no. moles and substituting in the known values and we have:
n = m/M
no. moles = 130.0g / (2x(22.99+3x14.01))
no. moles = 130.0/130.0 (4.s.f.)
no. moles = 1
Now we can use the ratio given in the equation to find the number of moles of Nitrogen that will be made:
1 x 3/2 = 1.5 moles of Nitrogen
Now we use the constant that 1 mole of any gas will always have a volume of 22.7dm^3 at STP.
1.5 x 22.7 = 34.05dm^3 of nitrogen gas.
Hope this helped!
