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adell [148]
3 years ago
13

If 50 mL of pure acetone is mixed with 450 mL of water, what is the percent by volume of acetone?

Chemistry
1 answer:
slega [8]3 years ago
4 0

Answer:

10%

Explanation:

The percent by volume of acetone is given by the following formula:

% v/v = Volume of acetone / Total Volume * 100%

Now we <u>calculate the total volume of the solution</u>:

Total Volume = Volume of Acetone + Volume of Water

Total Volume = 50 mL + 450 mL = 500 mL

Then we <u>calculate the percent by volume:</u>

% v/v = 50 mL / 500 mL * 100 % = 10%

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Explanation:

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An enzyme is discovered that catalyzes the chemical reaction SAD ↔ HAPPY A team of motivated researchers sets out to study the e
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The K_{m} of a substrate will be "10 μM".

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E_{t} = 20 \ nM

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As we know,

⇒  Vo=\frac{K_{cat}[E_{t}][S]}{K_{m}+[S]}

On putting the estimated values, we get

⇒  9.6=\frac{600\times 20\times 10^{-3}\times 40}{K_{m}+40}

⇒  K_{m}+40=\frac{600\times 20\times 10^{-3}\times 40}{9.6}

⇒  K_{m}+40=50

On subtracting "40" from both sides, we get

⇒  K_{m}+40-40=50-40

⇒  K_{m}=10 \ \mu M

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3 years ago
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3 years ago
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What is the molar mass of a gas if 0.102 g of the gas occupies 0.070 L at STP? a. 32.6g / mol b. 28.2 g/mol c. 40.0g / mol d. 47
alexgriva [62]

Answer:

A. 32.6 g/mol

Explanation:

First convert the volume of gas to moles using the ratio 1 mol / 22.4 L at STP.

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Now divide the grams of gas by the moles of gas:

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3 years ago
A ground state hydrogen atom absorbs a photon of light having a wavelength of 92.05 nm. It then gives off a photon having a wave
vodka [1.7K]
Absorbed photon energy
Ea = hc/λ.. (Planck's equation)
Ea = hc / 92.05^-9m 

<span>Energy emitted
Ee = hc/ 1736^-9m </span>

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∆E = Ea - Ee = hc(1/92.05<span>^-9 - 1/1736^-9) </span>
<span>∆E = (6.625^-34)(3.0^8) (1.028^7)
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En = - (13.60 / n²) </span>

n² = -13.60 / -0.85 = 16
n = 4
4 0
3 years ago
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