A sample of helium behaves as an ideal gas as energy is
1 answer:
Answer:
0.0321 g
Explanation:
Let helium specific heat
Assuming no energy is lost in the process, by the law of energy conservation we can state that the 20J work done is from the heat transfer to heat it up from 273K to 393K, which is a difference of ΔT = 393 - 273 = 120 K. We have the following heat transfer equation:
where is the mass of helium, which we are looking for:
You might be interested in
Answer:
1. a) 0.5 h = 1,800 s
h) 20 cm = 0.2 m
b) 2.0 h = 7,200 s
i) 5.0 kg = 5,000 g
c) 3.5 h = 12,600 s
j) 1.5 kg = 1,500 g
d) 1/4 h = 900 s
k) 450.0 g = 0.45 kg
e) 3.0 m = 300 cm
l) 20.0 g = 0.02 kg
f) 2.5 m = 250 cm
m) 500.0 g = 0.5 kg
g) 0.5 m = 500 mm
n) 1000.0 g = 1 kg