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AlladinOne [14]
3 years ago
12

NASA is giving serious consideration to the concept of solar sailing. A solar sailcraft uses a large, low mass sail and the ener

gy and momentum of sunlight for propulsion. (a) Should the sail be absorbing or reflective
Physics
1 answer:
Stella [2.4K]3 years ago
6 0

Answer:

Reflective

Explanation:

The radiation pressure of the wave that totally absorbed is given by;

P_{abs}= \frac{I}{C}

and While the radiation pressure of the wave totally reflected is given by;

P_{ref}= \frac{2I}{C}

Now compare the two-equation you can clearly see that the pressure due to reflection is larger than absorption therefore the sail should be reflective.

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Explain the difference between the three types of friction
USPshnik [31]
Static Friction

It is the friction that exists between a stationary object and the surface on which it's resting.


Sliding friction

It is the resistance created by two objects sliding against each other.

Rolling friction:-

It is the force resisting the motion when a body rolls on a surface.


hope this helps x
8 0
3 years ago
A car of mass 1000 kg is moving at 25 m/s. It collides with a car of mass 1200 kg moving at 30 m/s. When the cars collide, they
Alinara [238K]

Answer:

The total momentum of the cars before the collision is 61,000 kg.m/s

The total momentum of the cars after the collision is 61,000 kg.m/s

The velocity of the cars after the collision is 27.727 m/s

Explanation:

Given;

mass of the first car, m₁ = 1000 kg

initial velocity of the car, u₁ = 25 m/s

mass of the second car, m₂ = 1200 kg

initial velocity of the second car, u₂ = 30 m/s

The common velocity of the cars after collision = v

The total momentum of the cars before collision is calculated as;

P₁ = m₁u₁  +  m₂u₂

P₁ = (1000 x 25)  +  (1200 x 30)

P₁ = 61,000 kg.m/s

The total momentum of the cars after collision is calculated as;

P₂ = m₁v + m₂v

where;

v    is the common velocities of the cars after collision since they stick together.

P₂ = v(m₁ + m₂)

To determine "v" apply the principle of conservation of linear momentum for inelastic collision.

m₁u₁  +  m₂u₂  = v(m₁  + m₂)

(1000 x 25)  +  (1200 x 30) = v(1000 + 1200)

61,000 = 2,200v

v = 61,000/2,200

v = 27.727 m/s

The total momentum after collsion = v(m₁ + m₂)

                                                         = 27.727(1000 + 1200)

                                                          = 61,000 kg.m/s

Thus, momentum before and after collsion are equal.

8 0
3 years ago
Ned tightens a bolt in his car engine by exerting 15 N of force on his wrench at a distance of 0.45m from the fulcrum. How much
____ [38]

Answer:

T = 6.75\,N\cdot m

Explanation:

Vectorially speaking, torque is the cross product between force and distance from fulcrum. Its magnitude is equal to the following expression:

T = F\cdot r \cdot \sin \theta

T = F_{\bot} \cdot r

Let assume that force is perpendicular to the distance from the fulcrum. So, the torque needed to turn the bolt is:

T = (15\,N)\cdot (0.45\,m)

T = 6.75\,N\cdot m

8 0
4 years ago
This is for Personal Financial Literacy:
bulgar [2K]
I’m sure “save” is the correct answer, as it is the only grammatically correct answer choice. Also, it is easy to save when you know what you’ll have to pay for in the future.
8 0
3 years ago
A 77.0 kg firefighter climbs a flight of stairs 8.0 m high. how much work is required? 0 incorrect: your answer is incorrect. j
Alex73 [517]
<span>6160 joules

    to lift 1 newton 1 metre requires 1 joule
 there are 10 newtons in one kilo

    so 77(kg) x 8 (metres) x 10 (newtons/kilo) = 6160 joules</span>
5 0
3 years ago
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