Answer: The concentrations of A , B , and C at equilibrium are 0.1583 M, 0.2583 M, and 0.1417 M.
Explanation:
The reaction equation is as follows.
Initial : 0.3 0.4 0
Change: -x -x x
Equilbm: (0.3 - x) (0.4 - x) x
We know that, relation between standard free energy and equilibrium constant is as follows.
Putting the given values into the above formula as follows.
x = 0.1417
Hence, at equilibrium
= 0.1583 M
= 0.2583 M
The answer is <span>The components of a homogeneous mixture are evenly distributed.
In a homogeneous mixture, all components are evenly distributed. They are known as solutions. In a heterogeneous mixture, components are not evenly distributed. It consists of visibly different components. For example, milk is the homogeneous mixture, you cannot see its particles. But milk and cereals are the heterogeneous mixtures.</span>
C₆H₆ is benzene which has a molar mass of 78 g/mol. When benzene is burned, the reaction is called combustion. The heat produced in this reaction is called the heat of combustion. For benzene, the heat of combustion is -3271 kJ/mol.
Heat of benzene = (8.7 g)(1 mol/78 g)(-3271 kJ/mol) = -364.84 kJ
By conservation of energy,
Heat of benzene = - Heat of water
where
Heat of Water = mCp(Tf - T₀)
where Cp for water is 4.187 kJ/kg·°C
Thus,
-364.84 kJ = -(5691 g)(1 kg/1000 g)(4.187 kJ/kg·°C)(Tf - 21)
<em>Tf = 36.31°C</em>
I will need a picture if the periodic table
Answer:
Option B
Transfers energy to the water
Explanation:
Warm air transfers energy to the water when it flows over cold currents. This means that the warm air loses heat energy to the cold currents thus, raising its temperature.
Whenever there is a temperature difference between two bodies in contact with each other, the Fouriers law explains that there is always a transfer of heat from the hotter body to the colder body until they become the same temperature.
Thus, following this, heat will flow from the warm air to the cold currents.
