Ask question

Ask question

All categories

skelet666 [1.2K]

2 years ago

13

What is the acceleration of a the BMW i8 Roadster that goes from 0 to 60 mph in 3.8 seconds? A) in mi/h/s and b) in m/s^2

1 answer:

Nataly_w [17]2 years ago

8 0

Answer:

a) 15.78 mi/h/s

b) 7.105 m/s^2

Explanation:

a) It is given that speed changes from 0 to 60 miles per hour (mph)

Acceleration is equal to change in speed divided by time

$a = \frac{60-0}{3.8} \\a = 15.78$ mi/h/s

b)

1 mile/h = 0.45 m/s

Acceleration in m/s^2

$15.78 * 0.45 = 7.105$ m/s^2

You might be interested in

Write with all the steps and formulas and drawing if needed.

lianna [129]

<u>The answer is not contained detail explanation, just a solution and the required values. </u>

All the details are in the pictures, the answers are marked with orange colour.

Note,

in the task no 20.:

$m_A - the \ mass \ of \ A; \ m_B-the \ mass \ of \ B \ balls.\\V_A \ and \ V_B-the \ velocities \ of \ the \ A&B \ balls \ before \ collision.\\V'_A \ and \ V'_B-the \ velocities \ of \ the \ A&B \ balls \ after \ collision.$

V - the velocity of the pair of the balls after collision.

in the task no 21:

m₁ - the mass of the copper ball; m₂ - the mass of the copper calorimeter; m₃ - the mass of the water; t₀ - the initial temperature of water in the copper calorimeter; θ - the final temperature in the calorimeter after the copper ball is transferred into a copper calorimeter; t₁ - the required initial temperature of the copper ball before it is transferred into the calorimeter.

7 0

2 years ago

What is the difference in

maxonik [38]

<h3>Answer:</h3>

209.236 kg · m/s

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Physics</u>

<u>Momentum</u>

Momentum Formula: P = mv

P is momentum (in kg · m/s)
m is mass (in kg)
v is velocity (in m/s)

<h3>Explanation:</h3>

<u>Step 1: Define</u>

m₁ = 87.2 kg

v₁ = 2.87 m/s

m₂ = 0.0520 kg

v₂ = 789 m/s

<u>Step 2: Find Momentums</u>

<em>Football Player</em>

Substitute [MF]: P = (87.2 kg)(2.87 m/s)
Multiply: P = 250.264 kg · m/s

<em>Bullet</em>

Substitute [MF]: P = (0.0520 kg)(789 m/s)
Multiply: P = 41.028 kg · m/s

<u>Step 3: Find difference</u>

Define equation: P₁ - P₂
Substitute: 250.264 kg · m/s - 41.028 kg · m/s
Subtract: 209.236 kg · m/s

3 0

2 years ago

Read 2 more answers

Vector A⃗ points in the positive y direction and has a magnitude of 12 m. Vector B⃗ has a magnitude of 33 m and points in the ne

gavmur [86]

vector A has magnitude 12 m and direction +y

so we can say

$\vec A = 12 \hat j$

vector B has magnitude 33 m and direction - x

$\vec B = -33 \hat i$

Now the resultant of vector A and B is given as

$\vec A + \vec B = 12 \hat j - 33 \hat i$

now for direction of the two vectors resultant will be given as

$\theta = tan^{-1}\frac{12}{-33}$

$\theta = 160 degree$

so it is inclined at 160 degree counterclockwise from + x axis

magnitude of A and B will be

$R = \sqrt{A^2 + B^2}$

$R = \sqrt{12^2 + 33^2} = 35.11 m$

so magnitude will be 35.11 m

6 0

2 years ago

The impulse given to a ball with mass of 4 kg is 28 N s. If the ball were already moving at 3 m/s what would the final velocity

mart [117]

vf = 10 m/s. A ball with mass of 4kg and a impulse given of 28N.s with a intial velocity of 3m/s would have a final velocity of 10 m/s.

The key to solve this problem is using the equation I = F.Δt = m.Δv, Δv = vf - vi.

The impulse given to the ball with mass 4Kg is 28 N.s. If the ball were already moving at 3 m/s, to calculate its final velocity:

I = m(vf - vi) -------> I = m.vf - m.vi ------> vf = (I + m.vi)/m ------> vf = I/m + vi

Where I 28 N.s, m = 4 Kg, and vi = 3 m/s

vf = (28N.s/4kg) + 3m/s = 7m/s + 3m/s

vf = 10 m/s.

.

6 0

3 years ago

Why are citizens obligated to respond to such documents?

Zina [86]

To protect the constitutional right to confront ones accused

5 0

2 years ago