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makkiz [27]
3 years ago
13

Air is compressed in a piston-cylinder device. List three examples of irreversibilities that could occur

Engineering
1 answer:
KiRa [710]3 years ago
4 0

Answer:

While air is compressed in a piston cylinder there are following types of irreversibilities

1.Due to finite temperature difference heat transfer take place between cylinder and surrounding.

2.Due friction force between cylinder and piston .

3.Compression process is so fast due to this ,it leads in the irreversibility of system.

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Consider a cubic crystal with the lattice constant a. Complete the parts (a)-(c) below. (a) Sketch the crystallographic planes w
Anna [14]

Answer:

(a) See attachment

(b) The two planes are parallel because the intercepts for plane [220] are X = 0,5 and Y = 0,5 and for plane [110] are X = 1 and Y = 1. When the planes are drawn, they keep the same slope in a 2D plane.

(c) d = \frac{a}{\sqrt{h^{2} + k^{2} + l^{2}}} = \frac{1}{\sqrt{2}} =   0,707

Explanation:

(a) To determine the intercepts for an specific set of Miller indices, the reciprocal intercepts are taken as follows:

For [110]

X = \frac{1}{1} = 1; Y = \frac{1}{1} = 1; Z = \frac{1}{0} = \inf.

For [220]

X = \frac{1}{2} = 0,5;Y = \frac{1}{2} = 0,5;Z = \frac{1}{0} = \inf.

The drawn of the planes is shown in the attachments.

(b) Considering the planes as two sets of 2D straight lines with no intersection to Z axis, then the slope for these two sets are:

For (1,1):

K_1 = \frac{1}{1} = 1

For (0.5, 0.5):

K_2 = \frac{0.5}{0.5} = 1

As shown above, the slopes are exactly equal, then, the two straight lines are considered parallel and for instance, the two planes are parallel also.

(c) To calculate the d-spacing between these two planes, the distance is calculated as follows:

The Miller indices are already given in the statement. Then, the distance is:

\frac{1}{d^{2}} = \frac{h^{2} + k^{2} + l^{2}}{a^{2}}

d = \frac{a}{\sqrt{h^{2} + k^{2} + l^{2}}} = \frac{1}{\sqrt{2}} =   0,707

7 0
3 years ago
"Water is flowing in a metal pipe. The pipe OD (outside diameter) is 61 cm. The pipe length is 120 m. The pipe wall thickness is
Katarina [22]

Answer:

Total wight =640.7927 KN

Explanation:

Given that

do= 61 cm

L =120

t= 0.9 cm

That is why inner diameter of the pipe

di= 61 - 2 x 0.9 cm

di=59.2 cm

Water density ,ρ = 1 kg/L = 1000 kg/m³

Weight of the pipe ,wt = 2500 N/m

wt = 2500 x 120 N = 300,000 N

The wight of the water

wt ' = ρ V g

wt'=1000\times \dfrac{\pi}{4}\times (0.61^2-0.0592^2)\times 9.81\times 120 N

wt'=340792.47 N

That is why total wight

Total wight = wt + wt'

Total wight =300,000+ 340792.47 N

Total wight =640,792.47 N

Total wight =640.7927 KN

7 0
4 years ago
Quantitative meaning
pychu [463]

Answer:

Explanation:

relating to, measuring, or measured by the quantity of something rather than its quality.Often contrasted with qualitative.

6 0
3 years ago
Read 2 more answers
Someone needs to turn the crank to make the flywheel spin. Is this person creating energy? If not, where do you think the person
babymother [125]

Answer:

the person is creating energy in their muscels but they are not making energy in their flywheel its only in their body

Explanation:

8 0
4 years ago
transformer has 26 turns on the primary coil and 720 turns on the secondary coil. If this transformer is to produce an output of
hram777 [196]
<h2>Corrected Question:</h2>

A step-up transformer has 26 turns on the primary coil and 720 turns on the secondary coil. If this transformer is to produce an output of 4100 V with a 16-mA current, what input current and voltage are needed?

<h2>Answer:</h2>

The input current and voltage needed are 443 mA and 148 V respectively.

<h2>Explanation:</h2>

In a step-up transformer, the relationship between the number of turns in its primary coil (N_{p}), the number of turns in its secondary coil (N_{s}), the input voltage (V_{p}), the output voltage (V_{s}), the input current (I_{p}), and the output current (I_{s}) is given by;

\frac{N_{s} }{N_{p} } = \frac{V_{s} }{V_{p} } = \frac{I_{p} }{I_{s} }

This implies that;

\frac{N_{s} }{N_{p} } = \frac{V_{s} }{V_{p} }  ---------------------(i)

\frac{N_{s} }{N_{p} } = \frac{I_{p} }{I_{s} }  ---------------------(ii)

From the question;

N_{p} = 26 turns

N_{s} = 720 turns

V_{s} = 4100V

I_{s} = 16mA = 16 x 10⁻³A

(a) Substitute these values into equation (ii) as follows;

\frac{720}{26} = \frac{I_{p} }{16*10^{-3}}

Solve for I_{p};

I_{p} = 720 x 16 x 10⁻³ / 26

I_{p} = 443 x 10⁻³

I_{p} = 443 mA

Therefore the input current needed is 443mA

(b) Also, substitute those values into equation (i) as follows;

\frac{720}{26} = \frac{4100 }{V_{p} }

Solve for V_{p};

V_{p} = 4100 x 26 / 720

V_{p} = 148 V

Therefore, the input current needed is 148 V

5 0
3 years ago
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