The magnitude of the magnetic field inside the solenoid is 3.4×10^(-4) T.
To find the answer, we need to know about the magnetic field inside the solenoid.
<h3>What's the expression of magnetic field inside a solenoid?</h3>
- Mathematically, the expression of magnetic field inside the solenoid= μ₀×n×I
- n = no. of turns per unit length and I = current through the solenoid
<h3>What's is the magnetic field inside the solenoid here?</h3>
- Here, n = 290/32cm or 290/0.32 = 906
I= 0.3 A
- So, Magnetic field= 4π×10^(-7)×906×0.3 = 3.4×10^(-4) T.
Thus, we can conclude that the magnitude of the magnetic field inside the solenoid is 3.4×10^(-4) T.
Learn more about the magnetic field inside the solenoid here:
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Answer: 25.7m/s
Explanation: the cars have equal masses so we only consider their velocities,
The cars traveled together at 65° north of east this is with a velocity equal to the resultant velocity,
Using the force diagram as shown below;
Tan 65° = Vn/Ve
Ve is velocity of the car traveling east
Vn is velocity of car traveling north
Tan 65° = V2/12
2.144 = V2/12
V2 = 12 * 2.144
V2 = 25.7 m/s
It’s an example of gravitational potential energy
