The diagonals of a parallelogram bisect each other.
DH = HF and GH = HE
x + 5 = 2y
3x - 1 = 5y + 4
Solve the first equation for x.
x = 2y - 5
Now substitute 2y - 5 for x in the second equation.
3(2y - 5) - 1 = 5y + 4
6y - 15 - 1 = 5y + 4
6y - 16 = 5y + 4
y = 20
Now substitute 20 for y in the first original equation.
x + 5 = 2y
x + 5 = 2(20)
x + 5 = 40
x = 35
Answer: x = 35 and y = 20
Answer:
195
Step-by-step explanation:
To find the 23rd term of this sequence, we can use the arithmetic sequence formula 
where,
= 
term
= first term
= term position
= common difference
Answer:
Step-by-step explanation:
First, distribute the 2 to the 3z and -6 within the parenthesis.
You know have 6z -12/5 + 6 = 10
Subtract 6 from both sides of the equation
6z -12/5 = 4
Multiply 5 on both sides of the equation
6z -12 = 20
Add 12 to both sides of the equation
6z = 32
Divide by 6 on both sides of the equation
z = 32/6
Simplify
z = 16/3
I hope that this helps! :)
3)5 4/6 4) 13 8/10 5) 11 5/12 6) 11 10/24 7) 5 8/16 8) 15 8/20
