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4 years ago

What is the specific heat capacity of a material?

Physics

1 answer:

Talja [164]4 years ago

4 0

Answer/explanation :

It's the amount of heat that must be added OR removed from a unit mass of a substance to change its temperature by one degree Celsius.

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A gust of wind pushes a beach ball with a force of 9 newtons. The ball rolls 10 meters in 3 seconds. What is the power of the wi

taurus [48]

Power is the rate of doing work. So, it is expressed as

power = work done/ time

therefore power = force * distance/ time 

Power = 9 * 10 / 3 = 30W

Hope this answers the question. Have a nice day.

3 0

3 years ago

Read 2 more answers

You know that you sound better when you sing in the shower. This has to do with the amplification of frequencies that correspond

Lera25 [3.4K]

Answer: Length axis f= 114.3 Hz, Width axis f=228.67 Hz

Explanation:

We are given that,

Length of tub= 1.5 m

Width of tub= 0.75 m

Sound speed= 343 m/s

Now, we are also given shower is closed.

So, frequency is given as:

f= $m* \frac{v}{2L}$

For length axis

Put v= 343 m/s, m=1 and L=1.5 m

f= 1 * $\frac{343}{2*1.5}$

f= 114.3 Hz

For next resonant frequency, m=2

f= 2* $\frac{343}{2*1.5}$

f= 228.67

For width axis

Put v= 343 m/s, m=1 and L= 0.75 m

f= 1* $\frac{343}{2*0.75}$

f= 228.67 Hz

For next frequency, m=2

f= 2* $\frac{343}{2*0.75}$

f= 457.34 Hz

6 0

4 years ago

Someone please help with this

SSSSS [86.1K]

Answer:

The new force is 2/3 of the original force

Explanation:

Coulomb's Law

The electrical force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between the two objects.

Written as a formula:

$\displaystyle F=k\frac{q_1q_2}{d^2}$

Where:

$k=9\cdot 10^9\ N.m^2/c^2$

q1, q2 = the objects' charge

d= The distance between the objects

Suppose the first charge is doubled (2q1) and the second charge is one-third of the original charge (q2/3). Now the force is:

$\displaystyle F'=k\frac{2q_1*q_2/3}{d^2}$

Factoring out 2/3:

$\displaystyle F'=\frac{2}{3}k\frac{q_1*q_2}{d^2}$

Substituting the original force:

$F'=\frac{2}{3}F$

The new force is 2/3 of the original force

7 0

3 years ago

Indiana Jones is in a temple searching for artifacts. He finds a gold sphere with a radius of 2 cm sitting on a pressure sensiti

Vlad1618 [11]

Answer:

Volume of Sand = 0.4 m³

Radius of Sand Sphere = 0.46 m

Explanation:

First we need to find the volume of gold sphere:

Vg = (4/3)πr³

where,

Vg = Volume of gold sphere = ?

r = radius of gold sphere = 2 cm = 0.02 m

Therefore,

Vg = (4/3)π(0.2 m)³

Vg = 0.0335 m³

Now, we find mass of the gold:

ρg = mg/Vg

where,

ρg = density of gold = 19300 kg/m³

mg = mass of gold = ?

Vg = Volume of gold sphere = 0.0335 m³

Therefore,

mg = (19300 kg/m³)(0.0335 m³)

mg = 646.75 kg

Now, the volume of sand required for equivalent mass of gold, will be given by:

ρs = mg/Vs

where,

ρs = density of sand = 1602 kg/m³

mg = mass of gold = 646.75 kg

Vs = Volume of sand = ?

Therefore,

1602 kg/m³ = 646.75 kg/Vs

Vs = (646.75 kg)/(1602 kg/m³)

Vs = 0.4 m³

Now, for the radius of sand sphere to give a volume of 0.4 m³, can be determined from the formula:

Vs = (4/3)πr³

0.4 m³ = (4/3)πr³

r³ = 3(0.4 m³)/4π

r³ = 0.095 m³

r = ∛(0.095 m³)

r = 0.46 m

4 0

3 years ago

A horizontal spring required a force of 1.0 N to compress it 0.1 m. How much work is required to stretch the spring 0.4 m?

Crank

Answer:

Explanation:

given data

Force applied F= 1N

extension e= 0.1m

let us find the spring constant first

applying

F=ke

k=F/e

k=1/0.1

k=10N/m

Step two:

Required is the work done

we know that the expression/formula for the work done by a spring is given as

Wd=1/2kx^2

x=0.4m

substitute

Wd= 1/2*10*0.4^2

Wd=0.5*10*0.16

Wd=0.5J

3 0

3 years ago