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Alik [6]
3 years ago
11

For the equilibrium that exists in an aqueous solution of nitrous acid (HNO2, a weak acid), the equilibrium constant expression

is:_______a. K = [H+][NO2-]/[HNO2] b. K = [H+][N3+][O2-]^2/ [HNO2]c. K= [H+][NO2-] d. K = [H+]^2[NO-]/[HNO2]
Chemistry
1 answer:
Novosadov [1.4K]3 years ago
8 0

Answer:

a. K = [H+][NO2-]/[HNO2]

Explanation:

The computation of the expression of the equilibrium constant is shown below:

Given that the weak acid is HNO_2 that exist in the solution that aqueous

The dissociation equation of HNO_2

HNO_2(aq) \rightarrow NO_{2}^{-} (aq) + H^{+}(aq)

Now

Acidionization constant i.e.

k_a = \frac{[NO_{2}^{-}][H^{+}]}{HNO_{2}}

Therefore the correct option is a.

Hence, the same is to be considered

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