Question

For the equilibrium that exists in an aqueous solution of nitrous acid (HNO2, a weak acid), the equilibrium constant expression is:_______a. K = [H+][NO2-]/[HNO2] b. K = [H+][N3+][O2-]^2/ [HNO2]c. K= [H+][NO2-] d. K = [H+]^2[NO-]/[HNO2]

Answer 1

Answer:

a. K = [H+][NO2-]/[HNO2]

Explanation:

The computation of the expression of the equilibrium constant is shown below:

Given that the weak acid is HNO_2 that exist in the solution that aqueous

The dissociation equation of $HNO_2$

$HNO_2(aq) \rightarrow NO_{2}^{-} (aq) + H^{+}(aq)$

Now

Acidionization constant i.e.

$k_a = \frac{[NO_{2}^{-}][H^{+}]}{HNO_{2}}$

Therefore the correct option is a.

Hence, the same is to be considered