The acceleration of the given wave is 2.5m/s^2
<h3>Wave property</h3>
The standard wave function is expressed according to the equation
y = Asin(2πft+2πx/λ)
where
λ is the wave length
Given the equation below
y = 0.120 sin((π/8)x + 4πt)
Compare both equation to have:
(π/8)x = 2πx/λ
8 = 2/λ
λ = 2/8
λ = 1/4
λ = 0.25m
For the frequency
Compare both equation to have:
4πt = 2πft
4 = 2f
4/2 = 2f/2
f = 2 Hz
Speed = fλ
speed = 2(0.25)
speed = 0.5m/s
Determine the acceleration
acceleration = change in velocity/time
acceleration = 0.5/ 0.200
acceleration = 2.5m/s^2
Hence the acceleration of the given wave is2.5m/s^2
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Answer:

Explanation:
The magnitude of the magnetic field on the axis of the ring is given by:

is the permeability of free space,
is the flowing current through the ring,
is the ring's radius and
is the distance to the center of the ring.
The flowing current through the ring is defined as the ring's charge divided into the time taken by the charge to complete one revolution, that is, the period
. So, we have:

Now, replacing in (1):

Answer:
8.5m/s
Explanation:
We are given that
Mass of object=m=0.50 kg
Initial velocity, u=0
Force=F=2.88 N
Time=1.48 s
a.We know that

Using the formula



Using the formula


Hence, the velocity of the object at the end of this time interval=8.5m/s
Yes.objects of different masses can have the same kinetic energy