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creativ13 [48]
3 years ago
9

What is fact family for 3

Mathematics
1 answer:
kondor19780726 [428]3 years ago
7 0
8 and 24 let me know if this helps
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Multiply.
Kamila [148]
Expand the following:
(x - 6) (3 x^2 + 10 x - 1)
Hint: | Multiply out (x - 6) (3 x^2 + 10 x - 1).
 | | | | x | - | 6
 | | 3 x^2 | + | 10 x | - | 1
 | | | | -x | + | 6
 | | 10 x^2 | - | 60 x | + | 0
3 x^3 | - | 18 x^2 | + | 0 x | + | 0
3 x^3 | - | 8 x^2 | - | 61 x | + | 6:
Answer:  3 x^3 - 8 x^2 - 61 x + 6 Thus B:
7 0
3 years ago
A company manufactures and sells personalized stationery. The weekly fixed cost is $3850 and it cost $3.00 to produce each packa
Sveta_85 [38]

Answer:

  more than 1100

Step-by-step explanation:

The contribution margin for each package sold is ...

  $6.50 -3.00 = $3.50

The number of packages that must be sold to cover fixed costs is ...

  3.50n > 3850

  n > 1100 . . . . . . . divide by 3.50

The company will generate a profit if more than 1100 packages are produced and sold each week.

_____

<em>Additional comment</em>

If exactly 1100 packages are sold, then costs are covered, but profit is 0. In order for profit to be positive, more than 1100 packages must be sold.

5 0
2 years ago
Please help! Will mark brainliest! Not hard at all!
Trava [24]

Answer:

I think that the answer is A) $0.50

Step-by-step explanation:

So, if you want to figure out how much the strawberries cost for year 0, all you have to do is go to the point (0,4). For the first year the price of the strawberries have increased to 4.50. I know this because when you look at the graph, it looks like the point is in the middle of 4, which makes 4.50. So the price of the strawberries in year 1 is (1, 4.50). The price for year two is (2, 5) and so forth. This is what the pattern would be (0,4) (1, 4.50) (2, 5) (3, 5.50) (4,6) (5, 6.50) (6, 7) (7, 7.50) (8,8) (9, 8.50) (10, 9).......etc.

8 0
3 years ago
Read 2 more answers
Given that sin theta = 1/4, 0→theta→π/2, what<br>. what is the exact value of cos 8?​
natali 33 [55]
<h3>Answer: Choice B \frac{\sqrt{15}}{4}</h3>

===========================================================

Work Shown:

Angle theta is between 0 and pi/2, so this angle is in quadrant Q1.

Square both sides of the given equation

\sin \theta = \frac{1}{4}\\\\\sin^2 \theta = \left(\frac{1}{4}\right)^2\\\\\sin^2 \theta = \frac{1}{16}

Then use the pythagorean trig identity to get

\sin^2 \theta + \cos^2 \theta = 1\\\\\cos^2 \theta = 1-\sin^2 \theta\\\\\cos \theta = \sqrt{1-\sin^2 \theta} \ \ \ \text{cosine is positive in Q1}\\\\\cos \theta = \sqrt{1-\frac{1}{16}}\\\\\cos \theta = \sqrt{\frac{16}{16}-\frac{1}{16}}\\\\\cos \theta = \sqrt{\frac{16-1}{16}}\\\\\cos \theta = \sqrt{\frac{15}{16}}\\\\\cos \theta = \frac{\sqrt{15}}{\sqrt{16}}\\\\\cos \theta = \frac{\sqrt{15}}{4}\\\\

3 0
3 years ago
PLEASE HELP!!! Consider circle O, where m BD=70 and m CA=170
sveta [45]
BPD = 1/2(BD + CA)

BPD = 1/2(70 + 170)

BPD = 1/2(240)

BPD = 120

A full circle = 360 degrees

BC + AD = 360 - 70 - 170

BC+ AD = 360 - 240

BC + AD = 120

4 0
3 years ago
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