Astronaut X of mass 50kg floats next to Astronaut Y of mass 100kg while in space, as shown in the figure. The positive direction
is shown. Astronaut X applies a force against Astronaut Y such that the kinetic energy of each astronaut as a function of time is shown in the graph. What is the change in momentum of the two-astronaut system and the change in momentum of each astronaut from immediately before the force was applied to immediately after the force was applied?
1 answer:
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Explanation:
9 × 10^-3 × 13.59 = 0.122 N
Answer:
Explanation:
A car travels 6.0 km to the north and then 8.0 km to the east. The intensity of the position vector, in relation to the starting point is: a) 14 km b) 2.0 km c) 12 km d) 10 km e) 8.0 km
Check attachment for diagram
The intensity of the position vector is equal to the displacement,
So, to calculate the displacement, we need to find the length of the straight line from starting point to end point.
So, applying Pythagorean theorem
c² = a² + b²
R² = 6² + 36²
R² = 36 + 64
R² = 100
R = √100
R = 10 km.
Verifique el adjunto para ver el diagrama
La intensidad del vector de posición es igual al desplazamiento,
Entonces, para calcular el desplazamiento, necesitamos encontrar la longitud de la línea recta desde el punto inicial hasta el punto final.
Entonces, aplicando el teorema de Pitágoras
c² = a² + b²
R² = 6² + 36²
R² = 36 + 64
R² = 100
R = √100
R = 10 km.
