Answer: Volume would be 196.15 mL if the temperature were changed to and the pressure to 1.25 atmospheres.
Explanation:
Given: ,
= 256 mL,
= 720 torr (1 torr = 0.00131579 atm) = 0.947368 atm
,
Formula used to calculate volume is as follows.
Substitute the values into above formula as follows.
Thus, we can conclude that the volume would be 196.15 mL if the temperature were changed to and the pressure to 1.25 atmospheres.
Answer:
The volume of the air is 0.662 L
Explanation:
Charles's Law is a gas law that relates the volume and temperature of a certain amount of gas at constant pressure. This law says that for a given sum of gas at a constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases because the temperature is directly related to the energy of the movement they have. the gas molecules. This is represented by the quotient that exists between volume and temperature will always have the same value:
If you have a certain volume of gas V1 that is at a temperature T1 at the beginning of the experiment and several the volume of gas to a new value V2, then the temperature will change to T2, and it will be true:
In this case:
Replacing:
Solving:
V2=0.662 L
<u><em>The volume of the air is 0.662 L</em></u>
Answer:
CH3 - CH2 - NH - C(CH3)3
Explanation:
The 1HNMR is the acronym for Proton nuclear magnetic resonance and it is used in chemistry or Chemical laboratory for the analysis and identification of compounds.
In order to be able to answer the question accurately you have to have the tables containing all the values for chemical shift. The Chemical shift is measured in ppm and it occur due to Resonance frequency variation.
From the table, a singlet at 1.15 ppm (9H) is - C(CH3)3.
A singlet at d 0.9 ppm (1H) shows the presence of a secondary amine group, that is -R2NH group.
A triplet at 1.10 ppm (3H) shows that we have;
CH3- CH2-
A quartet at 2.6 ppm (2H) shows that we have;
-CH2 - CH3.
Therefore, joining all together we have;
CH3 - CH2 - NH - C(CH3)3.
Kindly check attached file for the picture of the structure.
1.51 x 10²⁵atoms
Explanation:
Given parameters:
Mass of Na = 578g
Unknown:
Number of atoms = ?
Solution:
To find the number of atoms, we must first find the number of moles the given mass contains.
Number of moles =
molar mass of Na = 23g
Number of moles = = 25.13moles
1 mole of a substance = 6.02 x 10²³atoms
25.13 mole of Na = 25.13 x 6.02 x 10²³atoms
This gives 1.51 x 10²⁵atoms of Na
Learn more:
Avogadro's constant brainly.com/question/2746374
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