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Artemon [7]
2 years ago
7

Mass is a fundamental physical quantity give scientific reason​

Physics
1 answer:
Lena [83]2 years ago
8 0

Answer:

yes

Explanation:

because it is independent of eachother

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You are given a (massless) piece of string that is L=1.45~\mathrm{m}L=1.45 m long, and tied to the end of it is an object of mas
bearhunter [10]

Answer:

   v = 4.25 m / s

Explanation:

To solve this exercise we must use Newton's second law, let's set a reference system that is horizontal and vertical

Axis y

           T_{y} - W = 0

X axis

            Tₓ = m a

The acceleration is centripetal

           a = v² / r

           Tₓ = m v² / r

            v² = Tₓ  r / m          (1)

Let's use trigonometry to find the tension components,  

           sin θ = Tₓ / T  

           cos θ =  T_{y}/ T  

           T_{y} = T cos θ  

           Tₓ = T sin θ

Let's look  angle for the maximum tension 103 N

             T_{y} = T cos θ = W  

             θ = cos⁻¹ W / T  

             θ = cos⁻¹ (5.77 9.8 / 103)  

             θ = 56.7°  

Now let's find the radius of the circle  

            sin 56.7 = r / L  

            r = L sin 56.7  

We substitute in the speed equation (1)  

            v² = T sin 56.7 L sin 56.7 / m  

            v = √ T L sin² 56.7 / m  

Let's calculate  

            v = √ (103 1.45 sin² 56.7 /5.77)  

v = 4. 25 m / s

6 0
4 years ago
Absolute pressure in tank is P1 = 260 kPa and local ambient absolute pressure is P2 =100 kPa. If liquid density in pipe is 13600
Pavlova-9 [17]

Answer:

1.176m

Explanation:

Local ambient pressure(P1) = 100 kPa

Absolute pressure(P2)=260kPa

Net pressure=absolute pressure-local ambient absolute pressure

Net pressure=P1(absolute pressure)-P2(local ambient absolute pressure)

Net pressure=260-100=160kPa

Pressure= ρgh

160kPa=13600*10*h

h=\frac{160000}{136000}

h=1.176m

5 0
3 years ago
1200 calories isfind the change in internal energy of the system 1200 calories is removed from a gas held at constant volume giv
Lostsunrise [7]
Divide those two then 300
7 0
3 years ago
Which of the following statements are true? Check all that apply. Check all that apply. The gravitational force between two obje
AveGali [126]

<em>The gravitational force between two objects is inversely proportional to the square of the distance between the two objects.</em>

The gravitational force between two objects is proportional to the product of the masses of the two objects.

The gravitational force between two objects is proportional to the square of the distance between the two objects.  <em> no</em>

The gravitational force between two objects is inversely proportional to the distance between the two objects.  <em> no</em>

The gravitational force between two objects is proportional to the distance between the two objects.  <em> no</em>

The gravitational force between two objects is inversely proportional to the product of the masses of the two objects. <em> no</em>

3 0
3 years ago
Read 2 more answers
A spring with a spring constant kk of 100 pounds per foot is loaded with 1-pound weight and brought to equilibrium. it is then s
tino4ka555 [31]

Given:

k = 100 lb/ft, m = 1 lb / (32.2 ft/s) = 0.03106 slugs 

Solution:


F = -kx 
mx" = -kx 
x" + (k/m)x = 0 

characteristic equation: 
r^2 + k/m = 0 
r = i*sqrt(k/m) 

x = Asin(sqrt(k/m)t) + Bcos(sqrt(k/m)t) 

ω = sqrt(k/m) 
2π/T = sqrt(k/m) 
T = 2π*sqrt(m/k) 
T = 2π*sqrt(0.03106 slugs / 100 lb/ft) 
T = 0.1107 s (period) 

x(0) = 1/12 ft = 0.08333 ft 
x'(0) = 0 

1/12 = Asin(0) + Bcos(0) 
B = 1/12 = 0.08333 ft 

x' = Aω*cos(ωt) - Bω*sin(ωt) 
0 = Aω*cos(0) - (1/12)ω*sin(0) 
0 = Aω 
A = 0 

So B would be the amplitude. Therefore, the equation of motion would be x = 0.08333*cos[(2π/0.1107)t]

5 0
4 years ago
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