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Delicious77 [7]
2 years ago
7

An arrow is shot parallel to horizontal from a height of 1.4 meters. It has a velocity of 49 m/s.

Physics
1 answer:
Mkey [24]2 years ago
5 0

The time taken for the arrow to hit the ground is 0.53 s.

The horizontal distance traveled by the arrow is 25.97 m.

The given parameters:

  • Initial horizontal velocity, v_x = 49 m/s
  • Initial vertical velocity, v_y = 0

<h3>What is time of motion?</h3>
  • This is the time taken for a projectile to land on the plane of projection.

The time of motion is calculated as follows;

h = v_yt + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 1.4}{9.8} }\\\\t = 0.53 \ s

The horizontal distance traveled by the arrow is calculated as follows;

X = v_x t\\\\X = (49\ m/s) \times (0.53 \ s)\\\\X = 25.97 \ m

Learn more about time of motion here: brainly.com/question/2364404

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