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Delicious77 [7]
2 years ago
7

An arrow is shot parallel to horizontal from a height of 1.4 meters. It has a velocity of 49 m/s.

Physics
1 answer:
Mkey [24]2 years ago
5 0

The time taken for the arrow to hit the ground is 0.53 s.

The horizontal distance traveled by the arrow is 25.97 m.

The given parameters:

  • Initial horizontal velocity, v_x = 49 m/s
  • Initial vertical velocity, v_y = 0

<h3>What is time of motion?</h3>
  • This is the time taken for a projectile to land on the plane of projection.

The time of motion is calculated as follows;

h = v_yt + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 1.4}{9.8} }\\\\t = 0.53 \ s

The horizontal distance traveled by the arrow is calculated as follows;

X = v_x t\\\\X = (49\ m/s) \times (0.53 \ s)\\\\X = 25.97 \ m

Learn more about time of motion here: brainly.com/question/2364404

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Along the remote Racetrack Playa in Death valley, California, stones sometimes gouge out prominent trails in the desert floor, a
REY [17]

Answer:

   F = 196 N

Explanation:

For this exercise we will use Newton's second law,  we define a reference system with the x axis in the direction of movement of the stones and the y axis vertically

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X axis

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In this case, they ask us for the force to keep moving, so the stones go at constant speed, which implies that the acceleration is zero.

       F- fr = 0

       F = fr

the friction force has the equation

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       fr = μ mg

we substitute

        F = μ mg

let's calculate

         F = 0.80 9.8 25

         F = 196 N

8 0
3 years ago
What is the value of n in the balmer series for which the wavelength is 410.2 nm.?
m_a_m_a [10]

The answer is n= 6.

What is Balmer series?

The Balmer series is the portion of the emission spectrum of hydrogen that represents electron transitions from energy levels n > 2 to n = 2. These are four lines in the visible spectrum. They are also known as the Balmer lines. The four visible Balmer lines of hydrogen appear at 410 nm, 434 nm, 486 nm and 656 nm.

For the Balmer series, the final energy level is always n=2. So, the wavelengths 653.6, 486.1, 434.0, and 410.2 nm correspond to n=3, n=4, n=5, and n=6 respectively. Since the last wavelength, 410.2 nm, corresponds to n=6, the next wavelength should logically correspond to n=7.

To solve for the wavelength, calculate the individual energies, E2 and E7, using E=-hR/(n^2). Then, calculate the energy difference between E2 (which is the final) and E7 (which is the initial). Finally, use lamba=hc/E to get the wavelength.

To learn more about emission spectrum click on the link below:

brainly.com/question/24213957

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2 years ago
How does a pin hole camera work? And how do we see through them?
DIA [1.3K]
A pinhole camera<span> is a simple </span>camera<span> without a lens but with a tiny aperture, a</span>pinhole<span> – effectively a light-proof box with a small hole in one side. Light from a scene passes through the aperture and projects an inverted image on the opposite side of the box, which is known as the </span>camera<span> obscura effect.</span>
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In a fission experiment observed by Hahn and Strassman, uranium-235 was bombarded by neutrons. The products of this ission react
wlad13 [49]

Answer:

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Explanation:

hope it helped u buddy

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