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AveGali [126]
3 years ago
11

Which term refers to the sum of the kinetic energy of all the particles in an object? O A. Heat O B. Potential energy O C. Therm

al energy O D. Temperature​
Chemistry
1 answer:
Zina [86]3 years ago
3 0

Answer:

C. Thermal energy

Explanation:

Thermal energy is the sum of the kinetic and potential energy of all the particles in an object.

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The standard biological reaction Gibbs energy for the removal of the phosphate group from adenosine monophosphate is 14 kJ mol-1
nignag [31]

Answer: K = 284

Explanation:

Gibbs free energy (DG) = RT(InK)

Where :

R = Gas constant = 8.314J/K/mol = 0.008314KJmol/K

T = temperature in Kelvin = 298K

K = dissociation rate

DG = 14

DG = RT(InK)

14 = 0.008314 × 298 × (InK)

14 = 2.477572 × InK

Ink = (14 ÷ 2.477542)

InK = 5.6507619

K = 284

7 0
3 years ago
Predict the ground-state electron configuration of the following ions. Write the answer in abbreviated form beginning with noble
Tanzania [10]

Answer: The ground-state electronic configuration of

1) Ru^{2+}=[Kr]4d^6

2) W^{3+]=4f^{14}5d^3

Explanation: The electronic configuration of elements is defined as the distribution of electrons around the nucleus of that element. It depends on the atomic number of the element.

Atomic number of the element = Number of electrons.

  • For Ru-element

Atomic number = 44

Number of electrons = 44

Electronic configuration of Ru-element = [Kr]4d^75s^1

To form Ru^{2+}, 2 electrons are released from the neutral Ru-element.

So, the electronic configuration of Ru^{2+}=[Kr]4d^6

  • For W-element

Atomic number = 74

Number of electrons = 74

Electronic configuration of W-element = [Xe]4f^{14}5d^46s^2

To form W^{3+}, 3 electrons are released from the neutral W-element.

So, the electronic configuration of W^{3+}=[Xe]4f^{14}5d^3

5 0
4 years ago
Read 2 more answers
The equilibrium constant, K., for the following reaction is 83.3 at 500 K. PC13(g) + Cl2(g) = PC13(E) Calculate the equilibrium
lord [1]

Answer:

The equilibrium concentration of PCl_5=0.228 M.

The equilibrium concentration of PCl_3=0.280 M -0.228 M=0.052M.

The equilibrium concentration of Cl_2=0.280 M -0.228 M=0.052M.

Explanation:

Answer:

The equilibrium concentration of HCl is 0.01707 M.

Explanation:

Equilibrium constant of the reaction = K_c=83.3

Moles of PCl_3 = 0.280 mol

Concentration of  [PCl_3]=\frac{0.280 mol}{1.00 L}=0.280 M

Moles of Cl_ = 0.280 mol

Concentration of [Cl_2]=\frac{0.280 mol}{1.00 L}=0.280M

           PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)

Initial:            0.280      0.280                            0

At eq'm:         (0.280-x)   (0.280-x)                     x

We are given:

[PCl_3]_{eq}=(0.280-x)

[Cl_2]_{eq}=(0.280-x)

[PCl_5]_{eq}=x

Calculating for 'x'. we get:

The expression of K_{c} for above reaction follows:

K_c=\frac{[PCl_5]}{[PCl_3][Cl_2]}

Putting values in above equation, we get:

83.3=\frac{x}{(0.280-x)\times (0.280-x)}

On solving this quadratic equation we get:

x = 0.228, 0.344

0.228 M < 0.280 M< 0.344 M

x = 0.228 M

The equilibrium concentration of PCl_5=0.228 M.

The equilibrium concentration of PCl_3=0.280 M -0.228 M=0.052M.

The equilibrium concentration of Cl_2=0.280 M -0.228 M=0.052M.

4 0
3 years ago
Determine whether each description represents a genotype or a phenotype.
ANEK [815]

Answer:

phenotype,phenotype,genotype,genotype,

genotype

Explanation:

phenotype is physical appearance and genotype is just like

yy Tt

8 0
3 years ago
Read 2 more answers
O, li, c which electrons experience the greatest effective nuclear charge? express your answer as a chemical formula.
Nataly_w [17]
<span>The effective nuclear charge of an atom = total electrons - inner electrons For O, ENC = 8 - 2 = 6 For Li, ENC = 3 - 2 = 1 For C, ENC = 6 - 2 = 4 The electrons in O experience the greatest effective nuclear charge and that is why O is smaller than C (which is smaller than Li).</span>
5 0
4 years ago
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