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3 years ago

Plssssssssssssssss help

Mathematics

2 answers:

cluponka [151]3 years ago

7 0

Answer:

EF is the chord of K

hope it helped

Elis [28]3 years ago

4 0

Answer:

EF is the chord of K

Step-by-step explanation:

plz mark me as brainliest

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If an 8 hour work day includes a total break time of 22 1/4%, how many hours are used for breaks?

torisob [31]

Answer:

1 39/50 hours. This is equivalent to 1.78 hours.

Step-by-step explanation:

The sum of the hours of work and the hours for break gives the work day hour which has been given as 8 hours.

Furthermore, given that the break time is 22 1/4%, the number of hours for break

= 22 1/4% × 8 hours

= 89/400 × 8

= 1 39/50 hours

4 0

3 years ago

The base length of a triangle is 8 feet and the height is 4 feet. What is the area of the triangle?

sweet [91]

8x4=32
32 divided by 2 = 16
the answer is 16 square feet

hope this helps :)

3 0

3 years ago

Read 2 more answers

Help me out please, im only typing this much because its making me...

Genrish500 [490]

Answer:

B. $x^{2} +2x-8$

Step-by-step explanation:

Here the best method to solve is by substituting the end values of the set in each option , otherwise it will a time consuming problem.

Now substitute x=-4 in all the options

A. $x^{2} -2x-8$

16+8-8=16>0

so out of option A and C option C is correct.

B. $x^{2} +2x-8$

16-8-8=0 which means for the values of x>-4 $x^{2} +2x-8$ is less than 0

Now substitute x=2 in all the options

A. $x^{2} -2x-8$

4-4-8=-8<0 . so option A and C both are incorrect.

B. $x^{2} +2x-8$

4+4-8=0 which means for the values of x<2 $x^{2} +2x-8$ is less than 0

Therefore the correct option is B

6 0

3 years ago

قالت تبيلة: هذه صديقتي، ... رينا، هي طالبة جديدة أيضا.

kobusy [5.1K]

Answer:

duk u what language is this

Step-by-step explanation:

osjzmzmnsmakzjk

nzjsjsjsm

ushdjsjskdjdm

mjsjsjsjsksjsj

hshsjajsnxjeomdms

3 0

3 years ago

Read 2 more answers

Classify ABC by its sides. Then determine whether it is a right triangle.

m_a_m_a [10]

Answer:

∴Given Δ ABC is not a right-angle triangle

a= AB = √45 = 3√5

b = BC = 12

c = AC = √45 = 3√5

Step-by-step explanation:

Given vertices are A(3,3) and B(6,9)

$AB = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2} }$

AB = $\sqrt{(9-3)^{2}+(6-3)^{2} } = \sqrt{6^{2}+3^{2} } =\sqrt{45}$

Given vertices are B(6,9) and C( 6,-3)

$B C = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2} }$

= $\sqrt{(-3-9)^{2}+(6-6)^{2} } =\sqrt{12^{2} } = 12$

BC = 12

Given vertices are A(3,3) and C( 6,-3)

$AC = \sqrt{(6-3)^{2}+(-3-3)^{2} } = \sqrt{9+36} = \sqrt{45}$

AC² = AB²+BC²

45 = 45+144

45 ≠ 189

∴Given Δ ABC is not a right angle triangle

5 0

3 years ago