Once potential energy is lost on a roller coaster it cannot be gained all the way back true or false
1 answer:
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Answer:
1. 77.31 N/m
2. 26.2 m/s
3. increase
Explanation:
1. According to the law of energy conservation, when she jumps from the bridge to the point of maximum stretch, her potential energy would be converted to elastics energy. Her kinetic energy at both of those points are 0 as speed at those points are 0.
Let g = 9.8 m/s2. And the point where the bungee ropes are stretched to maximum be ground 0 for potential energy. We have the following energy conservation equation
where m = 75 kg is the mass of the jumper, h = 72 m is the vertical height from the jumping point to the lowest point, k (N/m) is the spring constant and x = 72 - 35 = 37 m is the length that the cord is stretched
2. At 35 m below the platform, the cord isn't stretched, so there isn't any elastics energy, only potential energy converted to kinetics energy. This time let's use the 35m point as ground 0 for potential energy
where H = 35m this time due to the height difference between the jumping point and the point 35m below the platform
3. If she jumps from her platform with a velocity, then her starting kinetic energy is no longer 0. The energy conservation equation would then be
So the elastics energy would increase, which would lengthen the maximum displacement of the cord
Answer:
x = 0.327 m
Explanation:
Block 2 of mass 1.00 kg is at rest
spring constant = 200 N/m
Block 1 of mass 2 kg moving at 4 m/s
m₁ v₁ = (m₁ + m₂)V
2 x 4 = (2 + 1) V
V = 2.67 m/s
loss of kinetic energy = gain elastic potential energy
x = 0.327 m
hence, the spring compressed distance is equal to x = 0.327 m