Answer:
work=281.4KJ/kg
Power=4Kw
Explanation:
Hi!
To solve follow the steps below!
1. Find the density of the air at the entrance using the equation for ideal gases
where
P=pressure=120kPa
T=20C=293k
R= 0.287 kJ/(kg*K)=
gas constant ideal for air
2.find the mass flow by finding the product between the flow rate and the density
m=(density)(flow rate)
flow rate=10L/s=0.01m^3/s
m=(1.43kg/m^3)(0.01m^3/s)=0.0143kg/s
3. Please use the equation the first law of thermodynamics that states that the energy that enters is the same as the one that must come out, we infer the following equation, note = remember that power is the product of work and mass flow
Work
w=Cp(T1-T2)
Where
Cp= specific heat for air=1.005KJ/kgK
w=work
T1=inlet temperature=20C
T2=outlet temperature=300C
w=1.005(300-20)=281.4KJ/kg
Power
W=mw
W=(0.0143)(281.4KJ/kg)=4Kw
Answer:
a)
b)
Explanation:
Previous concepts
The cumulative distribution function (CDF) F(x),"describes the probability that a random variableX with a given probability distribution will be found at a value less than or equal to x".
The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution".
Part a
Let X the random variable of interest. We know on this case that
And we know the probability denisty function for x given by:
In order to find the cdf we need to do the following integral:
Part b
Assuming that , then the density function is given by:
And for this case we want this probability:
And evaluating the integral we got:
Answer:
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Answer:
The atmospheric pressure is 0.843 bar.
Explanation:
First, we calculate how much thermal energy (heat) was transferred to the water:
Knowing that all heat (Q) was used in making 1.19 kg of water boil (liquid to gas), we can find what is the latent heat () of this change of state (vaporization):
Looking up this value in a Water Heat of Vaporization Calculator, we find that it corresponds to a temperature of 94.9°C.
Knowing the temperature at which the water boils, we have to find the vapor pressure (the same as the latent heat according to temperature, it is a value which can be found in a table) at that temperature, which would be the atmospheric pressure of the location.
The vapor pressure of water at 94.9°C is 0.843 bar, i.e. the atmospheric pressure is 0.843 bar.