Here’s some of them
6. J
7. I
10. O
13. F
14. E
15. N
Answer:
a) The Net power developed in this air-standard Brayton cycle is 43.8MW
b) The rate of heat addition in the combustor is 84.2MW
c) The thermal efficiency of the cycle is 52%
Explanation:
To solve this cycle we need to determinate the enthalpy of each work point of it. If we consider the cycle starts in 1, the air is compressed until 2, is heated until 3 and go throw the turbine until 4.
Considering this:




Now we can calculate the enthalpy of each work point:
h₁=281.4KJ/Kg
h₂=695.41KJ/Kg
h₃=2105KJ/Kg
h₄=957.14KJ/Kg
The net power developed:

The rate of heat:

The thermal efficiency:

Answer with Explanation:
The capillary rise in 2 parallel plates immersed in a liquid is given by the formula

where
is the surface tension of the liquid
is the contact angle of the liquid
is density of liquid
'g' is acceleratioj due to gravity
'd' is seperation between thje plates
Part a) When the liquid is water:
For water and glass we have
Applying the values we get

Part b) When the liquid is mercury:
For mercury and glass we have
Applying the values we get

The negative sign indicates that there is depression in mercury in the tube.