Lower the melting point
Explanation:
Salts helps to melt road by lowering the melting point. It acts as an impurity and generally, impurities low the melting point of substances.
Salts are used as an antifreeze.
- Water freezes at 0°C and forms ice/snow which can impede human and vehicular movement.
- When salt is added, it causes the depression of the freezing point by lowering it further.
- The freezing point is pegged back at -6°C.
- This way it takes more low temperature to freeze the water.
- The salt acts as an impurity and causes the depression of melting point and widening of the melting range.
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Answer:
Enzyme Active Site and Substrate Specificity
There may be one or more substrates for each type of enzyme, depending on the particular chemical reaction. In some reactions, a single-reactant substrate is broken down into multiple products. In others, two substrates may come together to create one larger molecule.
Answer:
An increase in soil temperature increases microorganism growth because the rate of decomposition increases.
Explanation:
An increase in soil temperature increases microbial activities and the activity of extracellular enzymes that degrade polymeric organic matter within the soil. <u>An increase in the soil microbial activities means that the decomposition rate and microorganism growth would increase</u>. Increase in the activity of extracellular enzymes that degrade polymeric organic matter within the soil also means that more carbon dioxide would be produced and released into the atmosphere.
Answer:
The reaction is spontaneous when T> 0.98 Kelvin OR T> -272.17°C
Explanation:
Step 1: Data given
ΔH = 131.3 kJ/mol = 131300 J/mol
ΔS = 133.6 J/K*mol
T = 298K
Step 2: The balanced equation
C (s) + H2O (g) --> CO (g) + H2 (g)
Step 3: ΔG
For a reaction to be spontaneous, ΔG should be <0
When ΔG > 0 the reaction is spontaneous in the reverse direction.
ΔG = ΔH - TΔS
Since ΔG<0
ΔH - TΔS <0
Step 4: Calculate T where the reaction is spontaneous
ΔH - TΔS <0
131300 J/mol - T*133.6 J/K*mol <0
- T*133.6 J/K*mol < -131300 J/mol
-T <-131300 /133.6
-T< -982.8 Kelvin
T> 982.8 Kelvin OR T> 709.6°C
The reaction is spontaneous when T> 982.8 Kelvin OR T> 709.6°C
At 298 K this reaction C (s) + H2O (g) --> CO (g) + H2 (g) is <u>not spontaneous</u>
Answer:
x = 10/7
Explanation:
2(x + 2) - 4(2x - 3) = 4(2x - 1),
2x + 4 - 8x + 12 = 8x - 4,
-6x + 16 = 8x - 4,
20 = 14x,
x = 20/14 or 10/7
