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umka2103 [35]
3 years ago
5

What is true about past volcanic eruptions?

Chemistry
1 answer:
Nimfa-mama [501]3 years ago
4 0

Answer:

It is either

Past volcanic eruptions leave marks on rocks near the volcano.

Past volcanic eruptions leave marks in the atmosphere.

My guess is C.

Explanation:

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Which of the following is a matter phase in which the molecules are arranged on a matrix and close together a. Gas b. Liquid c.
Andrew [12]

Solid! The molecules in solid matter are arranged closely together and packed quite tightly to maintain a regular shape. Hope this helps!

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Calculate the volume of oxygen required to burn 12.00 l of ethane gas, c2h6, to produce carbon dioxide and water, if the volumes
kirza4 [7]
The  volume of   oxygen required  to  burn  12.00 L  ethane is calculated  as  follows

find the moles  of C2H6  used

At  STP  1 mole  is  always =  22.4 L, what about  12.00 L

= ( 12.00L  x 1 moles)  22.4 L = 0.536  moles

write the   reacting equation

2C2H6+  7O2 = 4CO2  + 6H2O
by  use  of mole  ratio  between  C2H6 :O2   which is 2:7  the  moles  of O2 

= 0.536  x7/2=  1.876  moles

again  at  STP  1mole =  22.4 L  what  about 1.876 moles

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8 0
4 years ago
Identify the spectator ions in this reaction. Check all that apply.
balandron [24]
CN, LI are the only two
4 0
3 years ago
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The octet rule states that atoms will gain, lose, or share valence electrons to get a full outer shell (orbital). Explain in you
bezimeni [28]

Answer:

In covalent bonding, the octet rule is important because sharing electrons gives both atoms a full valence shell. As a result, each atom can consider the shared electrons to be part of its own valence shell.

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6 0
3 years ago
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Molarity to percent by mass. Convert 1.672 mol/L MgCl2(aq) solution to percent by mass of MgCl2 in the solution. The solution de
nignag [31]

Answer:

\%m/m=14\%

Explanation:

Hello!

In this case, since the molarity of magnesium chloride (molar mass = 95.211 g/mol) is 1.672 mol/L and we know the density of the solution, we can first compute the concentration in g/L as shown below:

[MgCl_2]=1.672\frac{molMgCl_2}{L}*\frac{95.211gMgCl_2}{1molMgCl_2}=159.2\frac{gMgCl_2}{L}

Next, since the density of the solution is 1.137 g/mL, we can compute the concentration in g/g as shown below:

[MgCl_2]=159.2\frac{gMgCl_2}{L}*\frac{1L}{1000mL}*\frac{1mL}{1.137g}=0.14

Which is also the by-mass fraction and in percent it turns out:

\%m/m=0.14*100\%\\\\\%m/m=14\%

Best regards!

6 0
3 years ago
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