Answer:
B. The elements that have similar densities and atomic sizes
Explanation:
Answer:
Acid ammonium carbonate // Ammonium bicarbonate.
Explanation:
Hello, a 4 is missing in the fist H, thus:

The presence of the hydrogen between the ammonium and the carbonates characterizes the salt as an acid salt, so you could name it as acid ammonium carbonate or ammonium bicarbonate (similar to the sodium bicarbonate which is
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If you count the number of electrons (small dots), you have the atomic number. In this case you have 11 so this atom is a sodium atom. Sodium has 1 valence electron (electron on the outer shell) and chlorine has 7. This means that if sodium gave one electron away and chlorine would obtain one electron, they would both have the (ideal) noble gas conformation (full outer shell).
You can solve this by using the equation (P1V1/T1) = (P2V2/T2). Plug in 0.50 atm for P1, leave V1 as the unknown, and plug in 325 K as T1. Then substitute 1.2 atm for P2, 48 L for V2, and 320 K for T2. Solve for V1, which is 117L, but since you round using two sig figs, your answer is C, 120 L. Hope this helps!