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mash [69]
3 years ago
9

a balloon filled with 750.0 ml of helium at a temperature of 25 degrees celsius and an atmosphere pressure of 745 mm Hg. What vo

lume will the balloon have when it reaches an altitude where the temperature is -35 degrees celsius and the pressure is 0.60 atm?
Chemistry
1 answer:
Softa [21]3 years ago
4 0

Answer:

V₂ = 0.98 L

Explanation:

Given data:

Initial volume = 750 mL  =0.75 L

Initial pressure = 745 mmHg (745/760 =0.98 atm)

Initial temperature = 25 °C (25 +273 = 298 K)

Final temperature = -35°C (-35+273 = 238 K)

Final volume = ?

Final pressure = 0.60 atm

Formula:

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

P₁V₁/T₁ = P₂V₂/T₂  

V₂ = P₁V₁T₂/T₁ P₂

V₂ = 0.98 atm × 0.75 L × 238 K / 298 K × 0.60 atm

V₂ = 174.93 atm .L. K / 178.8  K.atm

V₂ = 0.98 L

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Answer:

c =0.2 J/g.°C

Explanation:

Given data:

Specific heat of material = ?

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Solution:

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Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

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ΔT =  40°C -20°C

ΔT =  20°C

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48 J =240 g.°C×c

c = 48 J/240 g.°C

c =0.2 J/g.°C

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3 years ago
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vesna_86 [32]

Answer:

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0 C= 273 k

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