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Ivenika [448]
3 years ago
5

Help :) For 100 points

Chemistry
2 answers:
Iteru [2.4K]3 years ago
4 0

Answer:

6. Color Change.

Production of an odor.

Change of Temperature.

Explanation:

That is the only one I know :)

Zinaida [17]3 years ago
3 0

Answer:

6. 3 things could potentially be, a change in mass, a change in color, or a change in weight. obviously there are more, but these are 3.

I'm sorry I couldn't answer more of these question of yours, I don;t know too much about aluminium :/

May I have brainliest please? :)

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The Russian chemist who designed the periodic table that was similar to the Periodic Table used today was _______________-
Xelga [282]
Dmitri Mendeleev, he realized that the physical and chemical properties of elements were related to their atomic mass and arranged them into groups (columns)
8 0
3 years ago
Given the following balanced equation, if the rate of O2 loss is 3.64 × 10-3 M/s, what is the rate of formation of SO3? 2 SO2(g)
Fynjy0 [20]

Answer:

Rate of formation of SO₃ [\frac{d[SO_{3}] }{dt}] = 7.28 x 10⁻³ M/s

Explanation:

According to equation   2 SO₂(g) + O₂(g) → 2 SO₃(g)

Rate of disappearance of reactants = rate of appearance of products

                     ⇒ -\frac{1}{2} \frac{d[SO_{2} ]}{dt} = -\frac{d[O_{2} ]}{dt}=\frac{1}{2} \frac{d[SO_{3} ]}{dt}  -----------------------------(1)

    Given that the rate of disappearance of oxygen = -\frac{d[O_{2} ]}{dt} = 3.64 x 10⁻³ M/s

             So the rate of formation of SO₃ [\frac{d[SO_{3}] }{dt}] = ?

from equation (1) we can write

                                   \frac{d[SO_{3}] }{dt} = 2 [-\frac{d[O_{2}] }{dt} ]

                                ⇒ \frac{d[SO_{3}] }{dt} = 2 x 3.64 x 10⁻³ M/s

                                ⇒ [\frac{d[SO_{3}] }{dt}] = 7.28 x 10⁻³ M/s

∴ So the rate of formation of SO₃ [\frac{d[SO_{3}] }{dt}] = 7.28 x 10⁻³ M/s

7 0
3 years ago
In one to two sentences, describe an experiment that would show that intramolecular forces (attractions between atoms within mol
Tatiana [17]

An experiment that would show that intramolecular forces are stronger than intermolecular forces will be heating a block of ice in a sealed container then allowing it to change to steam.

Intramolecular forces are the forces of attraction that hold atoms together within a molecule. Intramolecular forces require a high amount of energy to splits atoms or molecules in a chemical bonding.

Intermolecular forces are weaker forces of attraction that occur between molecules. They require lesser energy to splits molecules compared to intramolecular forces.

An experiment that would show that intramolecular forces are stronger than intermolecular forces will be heating a block of ice in a sealed container then allowing it to change to steam.

In the process, the energy required to change the state from ice to steam water is more than intermolecular forces.

Thus, we can conclude that this experiment shows that the intramolecular forces are stronger than the intermolecular forces.

Learn more about Intramolecular forces here:

brainly.com/question/13588164

3 0
2 years ago
What reaction would take place if hot tugsten was surrounded by air?
Inessa05 [86]

The reaction that would take place if hot tungsten was surrounded by air is that it would react to the oxygen in air to form non conducting tungsten oxide and burns out instantly.

8 0
3 years ago
Please help I will reward brainly
cupoosta [38]
The answer is glycolsis, I'm pretty sure.
4 0
3 years ago
Read 2 more answers
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