Question

Can you please help me and can you show your work please

Answer 1

Answer:

1. 25 moles water.

2. 41.2 grams of sodium hydroxide.

3. 0.25 grams of sugar.

4. 340.6 grams of ammonia.

5. 4.5x10²³ molecules of sulfur dioxide.

Explanation:

Hello!

In this case, since the mole-mass-particles relationships are studied by considering the Avogadro's number for the formula units and the molar mass for the mass of one mole of substance, we proceed as shown below:

1. Here, we use the Avogadro's number to obtain the moles in the given molecules of water:

$1.5x10^{25}molecules*\frac{1mol}{6.022x10^{23}molecules} =25 molH_2O$

2. Here, since the molar mass of NaOH is 40.00 g/mol, we obtain:

$1.2mol*\frac{40.00g}{1mol} =41.2g$

3. Here, since the molar mass of C6H12O6 is 180.15 g/mol:

$45g*\frac{1mol}{180.15g}=0.25g$

4. Here, since the molar mass of ammonia is 17.03 g/mol:

$20mol*\frac{17.03g}{1mol}=340.6g$

5. Here, since the molar mass of SO2 is 64.06 g/mol:

$48g*\frac{1mol}{64.06g} *\frac{6.022x10^{23}molecules}{1mol} =4.5x10^{23}molecules$

Best regards!