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BaLLatris [955]
3 years ago
8

A machinist turns the power on to a grinding wheel, at rest, at time t = 0 s. The wheel accelerates uniformly for 10 s and reach

es the operating angular velocity of 58 rad/s. The wheel is run at that angular velocity for 30 s and then power is shut off. The wheel slows down uniformly at 1.4 rad/s2 until the wheel stops. In this situation, the total number of revolutions made by the wheel is closest to:
Physics
2 answers:
natka813 [3]3 years ago
5 0

The total number of revolutions made by the wheel is closest to is 28.2 revolutions. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

dalvyx [7]3 years ago
5 0

Answer:

Ф=1716.8 Rev

Explanation:

A machinist turns the power on to a grinding wheel, at rest, at time t = 0 s. The wheel accelerates uniformly for 10 s and reaches the operating angular velocity of 58 rad/s. The wheel is run at that angular velocity for 30 s and then power is shut off. The wheel slows down uniformly at 1.4 rad/s2 until the wheel stops. In this situation, the total number of revolutions made by the wheel is closest to:

the time it takes to stop revolution will be found using this using this equation

ω2=final angular velocity

ω1=initial angular velocity

∝=angular deceleration

t=time

ω2=ω1+∝t

0=58 rad/s-1.4 rad/s^2t

t=58/1.4

t=39.28secs

to get the total number of revolution made by the wheel ,we get the area under the graph, which is a trapezium

Ф=1/2(20+39.2)*58

Ф=1716.8 Rev

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A mass of 0.5 kg hangs motionless from a vertical spring whose length is 1.10 m and whose unstretched length is 0.50 m. Next the
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Answer:

The maximum length during the motion is L_{max} = 1.45m

Explanation:

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          The initial speed is v_i = 1.3m/s

          The new length of the spring L_{new} =  1.30 m

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                           k = -\frac{F}{y}

Where F is the force applied  = m * g = 0.5 * 9.8=4.9N

           y is the difference in weight which is   =1.10-0.50=0.6m

The negative sign is because the displacement of the spring (i.e its extension occurs against the force F)

    Now  substituting values accordingly

                    k =  \frac{4.9}{0.6}

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  where D is this the is the displacement  

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             E_T = initial  \ elastic\ potential \ energy + kinetic \ energy

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Substituting value accordingly

                \frac{1}{2} *8.17 *D_{max}^2 =\frac{1}{2} * 8.17*(1.30 - 0.50)^2 + \frac{1}{2} * 0.5 *1.30^2

                4.085 * D_{max}^2 = 3.69

                 D^2_{max} = 0.9033

                D_{max} = 0.950m

So to obtain total length we would add the unstretched length

 So we have

                  L_{max} = 0.950 + 0.5 = 1.45m

                               

               

               

                 

                     

5 0
2 years ago
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Answer:

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d=\frac{42 kg}{22 m^3}=1.9 kg/m^3

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