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I am Lyosha [343]
3 years ago
7

PLZ HELP FAST BRANILIST IF RIGHT

Chemistry
1 answer:
malfutka [58]3 years ago
7 0

Answer:

Climate?

Explanation:

A German scientist who proposed the theory of continental drift ... Land reptile fossil located on multiple continents; evidence of continental drift ... climate evidence. Tropical plant fossils found on an island in Arctic Ocean, and glacier deposits ... Lystrosaurus (fresh water reptiles) found in places now separated by oceans

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Significant figures
Sergeu [11.5K]

Answer:

go look for that on google

Explanation:

4 0
3 years ago
How many isotopes does argon have?
Nostrana [21]
Argon has 24 known isotopes.
7 0
3 years ago
In which of these samples do atoms have the greatest kinetic energy
shepuryov [24]

Answer is: atoms have the greatest kinetic energy in liquid iron (2,000°C).

The average kinetic energy of molecules depends on the temperature. 

At high temperature(2,000°C), molecules of iron have greater kinetic energy than molecules of iron at low temperature (1,600°C, 65°C and 25°C)..

Read more on Brainly.com - brainly.com/question/8237916#readmore

7 0
3 years ago
The following balanced equation describes the reduction of iron(III) oxide to molten iron within a blast furnace: Fe2O3(s) + 3CO
Irina-Kira [14]

Answer:

Amount of excess Carbon (ii) oxide left over = 23.75 g

Explanation:

Equation of the reaction: Fe₂O₃ + 3CO ----> 2Fe + 3CO₂

Molar mass of Fe₂O₃ = 160 g/mol;

Molar mass of Carbon (ii) oxide = 28 g/mol

From the equation of reaction, 1 mole of Fe₂O₃ reacts with 3 moles of carbon (ii) oxide; i.e. 160 g of iron (iii) oxide reacts with 84 g (3 * 28 g)  of carbon (ii) oxide

450 g of Fe₂O₃ will react with 450 * 84/180) g of carbon (ii) oxide = 236..25 g of carbon (ii) oxide

Therefore the excess reactant is carbon (ii) oxide.

Amount of excess Carbon (ii) oxide left over = 260 - 236.25

Amount of excess Carbon (ii) oxide left over = 23.75 g

5 0
3 years ago
A solid powder is known to be a mixture of NaCl and Na2CO3, but the relative amounts of each compound in the sample are unknown.
AveGali [126]

Answer:

Concentration of sodium carbonate in the solution before the addition of HCl is 0.004881 mol/L.

Explanation:

Na_2CO_3(aq) +2 HCl(aq)\rightarrow 2NaCl(aq) + H_2O(l)+CO_2(g)

Molarity of HCl solution = 0.1174 M

Volume of HCl solution = 83.15 mL = 0.08315 L

Moles of HCl = n

molarity=\frac{moles}{Volume (L)}

0.1174 M=\frac{n}{0.08315 L}

n=0.1174 M\times 0.08315 L=0.009762 mol

According to reaction , 2 moles of HCl reacts with 1 mole of sodium carbonate.

Then 0.009762 mol of HCl will recat with:

\frac{1}{2}\times 0.009762 mol=0.004881 mol

Moles of Sodium carbonate = 0.004881 mol

Volume of the sodium carbonate containing solution taken = 1L

Concentration of sodium carbonate in the solution before the addition of HCl:

[Na_2CO_3]=\frac{0.004881 mol}{1 L}=0.004881 mol/L

4 0
3 years ago
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