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3 years ago

Consider the image above and select the answer that best represents the skiers energy.

Physics

1 answer:

Masteriza [31]3 years ago

7 0

Answer:

I need an image, but if you're talking about Potential and Kinetic energy, I will determine for you:

Explanation:

Potential Energy: stored energy that depends upon the relative position of various parts of a system.

Kinetic Energy: the form of energy that an object or a particle has by reason of its motion.

Therefore, if the skier is on top of the mountain, they would have potential energy since their energy from the ground to the top of the surface is stored. But, if the skier is in motion/mid-air from the top of a mountain, their energy is kinetic (in motion) because their stored energy (potential) is released as they step off of the surface.

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Problem 4 A meteoroid is first observed approaching the earth when it is 402,000 km from the center of the earth with a true ano

Nikitich [7]

Answer:

Part a: The eccentricity is 1.086.

Part b: The altitude at closest approach is 5088 km

Part c: The velocity at perigee is 8.516 km/s

Part d: The turn angle is 134.08 while the aiming radius is 5641.28 km

Explanation:

Specific energy is given by

$\epsilon=\frac{v^2}{2}-\frac{\mu}{r}$

Here

ε is the specific energy
v is the velocity which is given as 2.23 km/s
μ is the gravitational constant whose value is 398600
r is the distance between earth and the meteorite which is 402,000 km

$\epsilon=\frac{v^2}{2}-\frac{\mu}{r}\\\epsilon=\frac{2.2^2}{2}-\frac{398600}{402,000}\\\epsilon=1.495 km^2/s^2$

Value of specific energy is also given as

$\epsilon=\frac{\mu}{2a}\\a=\frac{\mu}{2\epsilon}\\a=\frac{398600}{2\times 1.495}\\a=13319 km$

Orbit formula is given as

$r=a(\frac{e^2-1}{1+ecos \theta})\\ae^2-recos\theta-(a+r)=0$

Putting values in this equation and solving for e via the quadratic formula gives

$ae^2-recos\theta-(a+r)=0\\(133319)e^2-(402000)(cos 150) e-(133319+402000)=0\\133319e^2+348142.21 e-535319=0\\\\e=\frac{-348142.21 \pm \sqrt{348142.21^2-4(133319)(535319)}}{2 (133319)}\\\\e=1.086 \, or \, -3.69$

As the value of eccentricity cannot be negative so the eccentricity is 1.086.

The radius of trajectory at perigee is given as

$r_p=a(e-1)\\$

Substituting values gives

$r_p=133319 (1.086-1)\\r_p=11465.4 km$

Now for estimation of altitude z above earth is given as

$z=r_p-R_E\\z=11465.4-6378\\z=5087.434\\z\approx 5088 km$

So the altitude at closest approach is 5088 km

radius of perigee is also given as

$r_p=\frac{h^2}{\mu}\frac{1}{1+e}$

Rearranging this equation gives

$h=\sqrt{r_p\mu(1+e)}\\h=\sqrt{11465.4 \times 3986000 \times (1+1.086)}\\h=97638.489 km^2/s$

Now the velocity at perigee is given as

$v_p=\frac{h}{r_p}\\v_p=\frac{97638.489}{11465.4}\\v_p=8.516 km/s\\$

So the velocity at perigee is 8.516 km/s

Turn angle is given as

$\delta =2 sin^{-1} (\frac{1}{e})$

Substituting value in the equation gives

$\delta =2 sin^{-1} (\frac{1}{e})\\\delta =2 sin^{-1} (\frac{1}{1.086})\\\delta =134.08$

Aiming radius is given as

$\Delta =a \sqrt{e^2-1}$

Substituting value in the equation gives

$\Delta =a \sqrt{e^2-1}\\\Delta =13319 \sqrt{1.086^2-1}\\\Delta=5641.28 km$

So the turn angle is 134.08 while the aiming radius is 5641.28 km

3 0

4 years ago

Nvm figured it out 1!!!1!3!2!1!3!

Natali [406]

Answer:

that's great, good job!

6 0

3 years ago

Which model is defined atomic model that describes an atom has a spherical object containing a certain number of electrons trapp

victus00 [196]

Answer:

C! Raisin Bread

Hope this helps you!

4 0

3 years ago

Read 2 more answers

Two simple pendulums are in two different places. The length of the second pendulum is 0.4 times the length of the first pendulu

faltersainse [42]

Answer:

$\sqrt{\frac{4}{9}}$

Explanation:

The frequency of a simple pendulum is given by:

$f=\frac{1}{2\pi}\sqrt{\frac{g}{L}}$

where

g is the acceleration of gravity

L is the length of the pendulum

Calling $L_1$ the length of the first pendulum and $g_1$ the acceleration of gravity at the location of the first pendulum, the frequency of the first pendulum is

$f_1=\frac{1}{2\pi}\sqrt{\frac{g_1}{L_1}}$

The length of the second pendulum is 0.4 times the length of the first pendulum, so

$L_2 = 0.4 L_1$

while the acceleration of gravity experienced by the second pendulum is 0.9 times the acceleration of gravity experienced by the first pendulum, so

$g_2 = 0.9 g_1$

So the frequency of the second pendulum is

$f_2=\frac{1}{2\pi}\sqrt{\frac{g_2}{L_2}}=\frac{1}{2\pi} \sqrt{\frac{0.9 g_1}{0.4 L_1}}$

Therefore the ratio between the two frequencies is

$\frac{f_1}{f_2}=\frac{\frac{1}{2\pi}\sqrt{\frac{g_1}{L_1}}}{\frac{1}{2\pi} \sqrt{\frac{0.9 g_1}{0.4 L_1}}}=\sqrt{\frac{0.4}{0.9}}=\sqrt{\frac{4}{9}}$

8 0

3 years ago

A truck of mass 500kg moving at 4m/s collides with another truck of mass 1500kg moving in the same direction at 2m/s. What is th

VMariaS [17]

Answer:

m1u1+m2u2=(m1+m2)v.

500×4+1500×2=(500+1500)V.

2000+3000=2000V.

5000=2000V.

V=2.5m/s

8 0

3 years ago