Answer:
k=188.46 N/m
Explanation:
Given that
m= 30 gm
Additional mass = ΔM
Lets take spring coefficient = k
at the equilibrium position
F= k Δl =( m + ΔM)g
Δl = change in the spring length
k Δl = ( m + ΔM)g
Δl = m g /k + g/k ΔM ---------------1
We know that equation of line given as
y = c + S x -----------------2
By compare equation 2 and 1
slope = s
S= g/k
Given that slope S= 0.052 m/kg
S =g/ k= 0.052
g=9.8 m/s²
9.8 = 0.052 k
k=188.46 N/m
So the spring constant is 188.46 N/m
Answer:
B) 6 W
Explanation:
First of all, we need to find the work done by the force. This is given by
where
F = 4 N is the magnitude of the force
d = 3 m is the distance through which the force is applied
Substituting,
Now we can find the power, which is given by
where
W = 12 J is the work done by the force
t = 2 s is the time taken
Substituting,
Answer:
The height from which the egg is dropped is <u>68.54 m</u>.
Explanation:
Given:
Initial velocity of egg is, (Dropped means initial velocity is 0)
Time taken is,
Acceleration experienced by egg is due to gravity,
The height from which the egg is dropped is,
Now, we use Newton's equation of motion that relates the distance, initial velocity, time and acceleration.
So, we have the following equation of motion:
Plug in all the given values and solve for 'd'. This gives,
Therefore, the height from which the egg is dropped is 68.54 m.
Answer: The time of contact will be 0.006 seconds.
Explanation:
An impulse of a force is the product of average force and the time interval when the force acts.
Mathematically,
Where,
J = impulse = 3.6 Ns
F = Force = 600N
= Time = ?s
Putting the values in above equation, we get:
t = 0.006 seconds
Hence, the time of contact will be 0.006 seconds.
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