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Monica [59]
3 years ago
11

A record of travel along a straight path is as follows: (a) Start from rest with constant acceleration of 3.9 m/s 2 for 15.3 s;

(b) Constant velocity of 59.67 m/s for the next 0.934 min; (c) Constant negative acceleration of −11.1 m/s 2 for 3.71 s. What was the total displacement
Physics
2 answers:
ValentinkaMS [17]3 years ago
8 0

Answer:

Total displacement Is 1410.9945 meters

Explanation:

The total displacement is as follows.

The first part = triangle A

3.9 m/s² for 15.3 sec.

3.9 * 15.3 = 59.67 m/s

Second part = rectangle

15.67 m/s for (0.934*60)sec= 56.04 sec

Third part = triangle B

11.1m/s² for 3.71 sec

11.1 * 3.71 = 41.171 m/s

The area if these shapes gives the displacement.

For A = 1/2(15.3*59.67)

= 456.4755 m

For B = 15.67 * 56.04

= 878.1468 m

For C = 1/2(41.171*3.71)

= 76.372

Total displacement = 456.4755 + 878.1468 + 76.3722

= 1410.9945 meters

ANTONII [103]3 years ago
3 0

Answer:

a) 456.48m

b) 3343.91m

c) - 76.376m

Total displacement = 3724.01m

Explanation:

Using kinematic equation for displacement

◇x1 = Vo t + 1/2 at^2

Where ◇x1 = displacement

Vo = initial velocity

a = acceleration

t = time

◇x1 = 0(15.3) + 1/2 (3.9)(15.3)^2

◇x1 = 0 + 456.48

Displacement = 456.48m

b) ◇x2 = Vt1

V = velocity = 59.67m/s

◇x2 = 59.67 ×0.934minute×60seconds

◇x2 = 59.67 ×56.04 = 3343.91

c)

a= -11.1m/s

= (-11.1 m/s^2× 3.71seconds)

◇ x3 =1/2 (41.18m/s ×3.71)

◇x3 =- 76.376m

Total displacement = ◇x1 + ◇x2 + ◇x3

Total displacement = 456.48 + 3343.91 - 76.376

Total displacement = 3724.01m

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3 years ago
A research submarine has a 20-cm-diameter window that is 9.0 cm thick. The manufacturer says the window can withstand forces up
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Answer:

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Inside pressure = 1.0 atm

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Using formula of pressure

P=\dfrac{F}{A}

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P=P_{atm}+\rho gh

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Equilibrium means their sum must be zero.

Here the forces are 5g, 6g, and 12g.

For number of forces to be in equilibrium the magnitude of largest vector should be less than sum of the magnitude of other vectors.

Here

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So this forces cannot form equilibrium.

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