Ask question

Ask question

All categories

3 years ago

13

1. Part A: Use the periodic table to order the following Period 3 elements from smallest to largest atomic radius: aluminum (Al)

, sulfur (S), and chlorine (Cl). Choose the appropriate order from the options below:

1 answer:

nalin [4]3 years ago

3 0

Answer:

chlorine, aluminum, sulfur....i think im not sure

Explanation:

You might be interested in

Does rapidly cooled rock contain small crystals?

Lisa [10]

I believe they do, yes.

3 0

3 years ago

ASAP NEED HELP, WILL MARK BRAINLEST, WHEN ASKING A QUESTION I REPEAT DO NOT ASK IT IN THE ANSWER SECTION, THANKS FOR READING. (b

kicyunya [14]

Answer:

Look at the images/files below :) Hope it helps Have a great day!

Explanation:

7 0

3 years ago

Read 2 more answers

The solubility of carbon dioxide in water is 0.161 g CO2in 100 mL of water at 20ºC and 1.00 atmCO2. A soft drink is carbonated w

Sedbober [7]

<u>Answer:</u> The solubility of carbon dioxide at 5.50 atm is $0.886g/100mL$

<u>Explanation:</u>

To calculate the molar solubility, we use the equation given by Henry's law, which is:

$C_{A}=K_H\times p_{A}$

Or,

$\frac{C_{1}}{C_{2}}=\frac{p_{1}}{p_2}$

where,

$C_1\text{ and }p_1$ are the initial concentration and partial pressure of carbon dioxide

$C_2\text{ and }p_2$ are the final concentration and partial pressure of carbon dioxide

We are given:

$C_1=0.161g/100mL\\p_1=1.00atm\\C_2=?\\p_2=5.50atm$

Putting values in above equation, we get:

$\frac{0.161g/100mL}{C_2}=\frac{1.00atm}{5.50atm}\\\\C_2=\frac{0.161g/100mL\times 5.50atm}{1.00atm}=0.886g/100mL$

Hence, the solubility of carbon dioxide at 5.50 atm is $0.886g/100mL$

4 0

4 years ago

What is the most precise measurement this beaker can give?

allochka39001 [22]

<span>a.the nearest 1 ml

1 mL is much more precise than 100 mL because 1 mL is a very small and precise unit of measurement</span>

8 0

4 years ago

Bauxite is an ore that contains the element aluminum. If you obtained 108 grams of aluminum from an ore sample that initially we

Stels [109]

Answer:

53% aluminium is present.

Explanation:

Given data:

Mass of aluminium in bauxite = 108 g

Total mass of sample = 204 g

Percentage of aluminium = ?

Solution:

Formula:

Percentage = Mass of aluminium / total mass of sample× 100

Now we will put the values in formula:

Percentage = 108 g/204 × 100

Percentage = 0.53 × 100

Percentage = 53%

So in given 204 g of bauxite there is 53% aluminium is present.

8 0

3 years ago